The volume occupied by 1 mole of diatomic gas particle at NTP ( Normal Temperature & Pressure) is 11.2 L
1 mole of gas particles at STP (Standard Temperature and Pressure) occupies a volume of 22.4 liters.
This depends on the temperature and the pressure. At standard temperature and pressure 1 mole will occupy 22.4 L, so multiply... 22.4 x 2.22 = 48.728 L at STP.
The molar mass of diatomic nitrogen (N2) is approximately 28.02 g/mol. Therefore, the mass of one mole of diatomic nitrogen gas is 28.02 grams.
1 mole occupies 22.4 liters. 0.5 moles occupies 11.2 liters at STP.
PV=nRT 32 gram O2 = 1 mole O2 (1atm)(V) = (1 mole)(.0821)(273) V = 22.4 L
1 mole of gas particles at STP (Standard Temperature and Pressure) occupies a volume of 22.4 liters.
The volume is 64,8 L.
A 0.50 mole sample of helium will occupy a volume of 11.2 liters under standard temperature and pressure (STP) conditions, which are 0 degrees Celsius (273.15 K) and 1 atmosphere pressure. At STP, one mole of any gas occupies a volume of 22.4 liters.
At STP, 1 mole of a gas will occupy 22.4 liters; or 0.5 mole will occupy 11.2 liters.
22.4 L. At STP 1 mole of any gas will always be equal to 22.4 L.
At STP (standard temperature and pressure), all gases have the same volume of 22.4 liters per mole regardless of their identity. Therefore, 1.00 mole of each gas would occupy the same volume of 22.4 liters.
One mole represents the same number of particles, regardless of the substance. Since the volume that a mole occupies is determined by the substance's molar mass and density, one mole of any substance at the same conditions of temperature and pressure will have the same volume.
This depends on the temperature and the pressure. At standard temperature and pressure 1 mole will occupy 22.4 L, so multiply... 22.4 x 2.22 = 48.728 L at STP.
At standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters. Therefore, a volume of 22.4 liters will be occupied by 1 mole of Cl2 gas at STP.
The molar mass of diatomic nitrogen (N2) is approximately 28.02 g/mol. Therefore, the mass of one mole of diatomic nitrogen gas is 28.02 grams.
1 mole occupies 22.4 liters. 0.5 moles occupies 11.2 liters at STP.
PV=nRT 32 gram O2 = 1 mole O2 (1atm)(V) = (1 mole)(.0821)(273) V = 22.4 L