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At room temperature and pressure (RTP), which is typically defined as 20°C and 1 atmosphere, 1 mole of gas particles occupies approximately 24.0 liters. This volume is derived from the ideal gas law under standard conditions for gases. The specific volume may vary slightly depending on the gas and its properties, but 24.0 liters is a commonly accepted value for many gases at RTP.
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Under what sets of condition will a 0.50 mole sample of helium occupy a volume of 11.2 liters?
A 0.50 mole sample of helium will occupy a volume of 11.2 liters under standard temperature and pressure (STP) conditions, which are 0 degrees Celsius (273.15 K) and 1 atmosphere pressure. At STP, one mole of any gas occupies a volume of 22.4 liters.
Under what sets of conditions will a 0.50 mole sample of helium occupy a volume of 11.2 liters?
At STP, 1 mole of a gas will occupy 22.4 liters; or 0.5 mole will occupy 11.2 liters.
Given 1.00 mole of each what gases at STP which gas would have the greatest volume?
At STP (standard temperature and pressure), all gases have the same volume of 22.4 liters per mole regardless of their identity. Therefore, 1.00 mole of each gas would occupy the same volume of 22.4 liters.
What volume will the Cl2 occupy at STP?
At standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters. Therefore, a volume of 22.4 liters will be occupied by 1 mole of Cl2 gas at STP.
What volume will 1.50 mol of C2H4 gas occupy at STP?
1 mole gas = 22.4L 1.5mol C2H4 x 22.4L/mol = 33.6L ethane gas (C2H4)
What volume does 1 mole of gas particles occupy at stp?
1 mole of gas particles at STP (Standard Temperature and Pressure) occupies a volume of 22.4 liters.
What volume does 1 mole of diatomic gas particles occupy at NTP?
At NTP (normal temperature and pressure), 1 mole of any gas occupies approximately 24 liters of volume. This is due to the ideal gas law, which relates the volume, pressure, temperature, and amount of gas.
Under what sets of condition will a 0.50 mole sample of helium occupy a volume of 11.2 liters?
A 0.50 mole sample of helium will occupy a volume of 11.2 liters under standard temperature and pressure (STP) conditions, which are 0 degrees Celsius (273.15 K) and 1 atmosphere pressure. At STP, one mole of any gas occupies a volume of 22.4 liters.
One mole of N2 gas at STP will occupy what volume?
22.4 L. At STP 1 mole of any gas will always be equal to 22.4 L.
What does the volume of gas depend on?
The volume of gas depends on the temperature, pressure, and number of gas particles present. These factors affect the amount of space the gas particles occupy.
Under what sets of conditions will a 0.50 mole sample of helium occupy a volume of 11.2 liters?
At STP, 1 mole of a gas will occupy 22.4 liters; or 0.5 mole will occupy 11.2 liters.
Given 1.00 mole of each what gases at STP which gas would have the greatest volume?
At STP (standard temperature and pressure), all gases have the same volume of 22.4 liters per mole regardless of their identity. Therefore, 1.00 mole of each gas would occupy the same volume of 22.4 liters.
How do you increase the volume of a gas without changing its particles?
You can increase the volume of a gas by increasing the pressure applied to it. By compressing the gas into a smaller space, the gas particles will occupy a larger volume due to the increased pressure. This does not change the number or type of particles present in the gas.
According to Avogadro's Law what characteristic of 1 mole of gas at STP?
It occupies 22.4 L
What volume will the Cl2 occupy at STP?
At standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters. Therefore, a volume of 22.4 liters will be occupied by 1 mole of Cl2 gas at STP.
Does a real gas have volume?
Yes, a real gas has volume because its particles occupy physical space. Unlike an ideal gas, which is assumed to have no volume and incompressible point particles, real gases have finite molecular sizes and experience intermolecular interactions that result in volume occupancy.
What volume will 1.50 mol of C2H4 gas occupy at STP?
1 mole gas = 22.4L 1.5mol C2H4 x 22.4L/mol = 33.6L ethane gas (C2H4)
