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What volume (in liters) does 2.895 mole of oxygen occupy at STP?
The volume is 64,8 L.
Under what sets of condition will a 0.50 mole sample of helium occupy a volume of 11.2 liters?
A 0.50 mole sample of helium will occupy a volume of 11.2 liters under standard temperature and pressure (STP) conditions, which are 0 degrees Celsius (273.15 K) and 1 atmosphere pressure. At STP, one mole of any gas occupies a volume of 22.4 liters.
What volume does 1 mole of gas particles occupy at stp?
1 mole of gas particles at STP (Standard Temperature and Pressure) occupies a volume of 22.4 liters.
What volume does 22g of CO2 at STP occupy?
This depends on the temperature and the pressure. At standard temperature and pressure 1 mole will occupy 22.4 L, so multiply... 22.4 x 2.22 = 48.728 L at STP.
What volume will the Cl2 occupy at STP?
At standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters. Therefore, a volume of 22.4 liters will be occupied by 1 mole of Cl2 gas at STP.
What does a molar volume of a gas at STP occupy?
At STP (standard temperature and pressure), one mole of any gas occupies a volume of 22.4 liters. This is known as the molar volume of a gas at STP.
What volume does 0.50 mole of NH3 at STP occupy?
1 mole occupies 22.4 liters. 0.5 moles occupies 11.2 liters at STP.
According to Avogadro's Law what characteristic of 1 mole of gas at STP?
It occupies 22.4 L
Under what sets of conditions will a 0.50 mole sample of helium occupy a volume of 11.2 liters?
At STP, 1 mole of a gas will occupy 22.4 liters; or 0.5 mole will occupy 11.2 liters.
What is a volume in liters of one mole of gas at STP first letter is a c?
Not sure what you mean by "first letter is a c", but the volume of one mole of an ideal gas at STP is 22.4 Liters.
At STP 32 grams of O2 would occupy the same volume as?
PV=nRT 32 gram O2 = 1 mole O2 (1atm)(V) = (1 mole)(.0821)(273) V = 22.4 L
What volume does 0685 mol of gas occupy at stp?
At standard temperature and pressure (STP), one mole of an ideal gas occupies 22.4 liters. Therefore, to find the volume occupied by 0.685 mol of gas at STP, you can multiply the number of moles by the volume per mole: 0.685 mol × 22.4 L/mol = 15.34 liters. Thus, 0.685 mol of gas occupies approximately 15.34 liters at STP.
