This depends on the temperature and the pressure.
At standard temperature and pressure 1 mole will occupy 22.4 L, so multiply...
22.4 x 2.22 = 48.728 L at STP.
One mole of gas.
2.355 L
We know that one mole of any gas at STP occupies 22.4 liters of volume. We also know that one mole of carbon dioxide is 44.01 grams of CO2. If there are 44.01 grams of this gas in 22.4 liters at STP, then there will be about 0.98 grams of CO2 in half a liter (500 ml) of the gas at STP.
molar volume
The volume is 102 mL.
22.4 liters at STP
61ml
stupid question
We know that one mole of any gas at STP occupies 22.4 liters of volume. We also know that one mole of carbon dioxide is 44.01 grams of CO2. If there are 44.01 grams of this gas in 22.4 liters at STP, then there will be about 0.98 grams of CO2 in half a liter (500 ml) of the gas at STP.
This volume is 79,79 litres.
The volume is approx. 15,35 litres.
The volume is 64,8 L.
The volume of ammonia is 19,5 L.
molar volume
0.00922 g of H2 gas will occupy approximately 0.100 L at STP
The volume is 102 mL.
5126 cm3
22.4 liters at STP
61ml