The volume is 22,710 980(38) litres for the ideal gas.
It occupies 22.4 L
At standard temperature and pressure (STP), 1 mole of any gas occupies 22.4 liters. Therefore, a volume of 22.4 liters will be occupied by 1 mole of Cl2 gas at STP.
Using the ideal gas law, at STP (standard temperature and pressure), 1 mole of gas occupies 22.4 liters. Therefore, a balloon with 560 liters at STP would contain 25 moles of gas (560 liters / 22.4 liters/mole).
1 mole gas = 22.4L 1.5mol C2H4 x 22.4L/mol = 33.6L ethane gas (C2H4)
One mole of O₂ gas occupies approximately 22.4 liters at standard temperature and pressure (STP), which is 0 degrees Celsius and 1 atmosphere of pressure. The molar mass of O₂ is about 32 grams, meaning that 1 mole of O₂ weighs 32 grams. Thus, under STP conditions, 1 mole of O₂ gas will have both a specific volume and mass.
1 mole of an ideal gas at STP occupies 22.4 liters. If STP is 'close' to the boiling point a real gas may deviate from ideal behavior and thus the volume will not be as predicted.
It occupies 22.4 L
1 mole of gas at STP (standard temperature and pressure) occupies 22.4 liters of volume. This is known as the molar volume of a gas at STP. Additionally, the gas has a pressure of 1 atmosphere and a temperature of 273 K at STP.
It occupies 22.4 L
It occupies 22.4 L
1 mole of gas at STP occupies 22.4 liters.
It occupies 22.4 L
1 mole of gas at STP occupies 22.4 liters.
22.4 L. At STP 1 mole of any gas will always be equal to 22.4 L.
1 mole of gas at STP occupies 22.4 liters.
1 mole of gas at STP occupies 22.4 liters.
1 mole of gas particles at STP (Standard Temperature and Pressure) occupies a volume of 22.4 liters.