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One mole of O₂ gas occupies approximately 22.4 liters at standard temperature and pressure (STP), which is 0 degrees Celsius and 1 atmosphere of pressure. The molar mass of O₂ is about 32 grams, meaning that 1 mole of O₂ weighs 32 grams. Thus, under STP conditions, 1 mole of O₂ gas will have both a specific volume and mass.
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How many liters of water can be made from 5 L of oxygen gas and an excess of hydrogen?
55 grams O2 × (1 mol O2 ÷ 32 g O2) × (2 mol H2O ÷ 1 mol O2) × (22.4 L ÷ 1 mol H2O) = 77 L H2O(g)In the liquid form, it works out to just under 62 milliliters.
Which must be the same when comparing 1 mol of oxygen gas O2 with 1 mol of carbon monoxide gas CO?
When comparing 1 mol of oxygen gas (O₂) with 1 mol of carbon monoxide gas (CO), the number of molecules must be the same, as both contain 1 mol. Additionally, both gases will have the same volume under standard temperature and pressure conditions, which is approximately 22.4 liters. However, their molar masses and chemical properties differ significantly.
The number of moles of h2o formed when 1 mole of o2 reacts with c5h12 in the reaction c5h12 plus 8o2 equals 5co2 plus 6h2o is?
C5H12 + 8 O2 --> 5 CO2 + 6 H2O (1 mol O2)(6 mol H2O/8 mol O2) = 0.75 mol H2O
What is the balanced equation for The total number of grams of CO2 that are produced when 4 grams of C are added to 10.67 grams of O2?
The balanced equation is: 2C + O2 -> 2CO2. First, determine the moles of C and O2: 4g C / 12 g/mol = 0.33 mol C and 10.67g O2 / 32 g/mol = 0.33 mol O2. From the balanced equation, 2 moles of C produces 2 moles of CO2, so 0.33 mol C will produce 0.33 mol CO2. Since CO2 has a molar mass of 44 g/mol, the total grams of CO2 produced will be: 0.33 mol CO2 x 44 g/mol = 14.52 grams of CO2.
Calculate the number of atoms of O contained in 16.0 pounds of O?
To calculate the number of oxygen atoms in 16.0 pounds of oxygen, first convert 16.0 pounds to grams (1 pound ≈ 453.592 grams). Then, calculate the number of moles of oxygen using the molar mass of oxygen (16.00 g/mol). Finally, use Avogadro's number (6.022 x 10^23 atoms/mol) to find the number of oxygen atoms.
How much mass does 1 mol of o2 gas have?
15.99 x 2 g
How many liters of water can be made from 5 L of oxygen gas and an excess of hydrogen?
55 grams O2 × (1 mol O2 ÷ 32 g O2) × (2 mol H2O ÷ 1 mol O2) × (22.4 L ÷ 1 mol H2O) = 77 L H2O(g)In the liquid form, it works out to just under 62 milliliters.
What is the volume of oxygen that will be used by 12g of Mg to be completely converted into MgO?
The reaction : Mg + O2-----------> MgO The balanced reaction : 2 Mg + O2-----------> 2 MgO that is 2 moles of Mg reacts with one mole of oxygen gas. moles of Mg reacted = 12 g / 24 g mol-1=0.5 mol. Thus the no. of mol of O2 reacted = 0.5 mol /2 =0.25 mol If the gas is at standard temperature and pressure, then Volume of 1 mol of O2 gas = 22.4 dm3 Volume of 0.25 mol of O2 gas = 22.4 x 0.25 dm3= 5.6 dm3 the volume of oxygen that will be used to react completely with 12 g Mg =5.6 dm3 (provided that the gas is at the standard conditions.)
How many moles of ozone O3 could be formed from 96.0g of oxygen gas O2?
Using the molar mass of oxygen (O2) which is 32 g/mol, you can calculate that you have 3 moles of oxygen gas. Since the ratio of O3 to O2 is 1:2, you would form 1.5 moles of ozone (O3) from 96.0g of O2.
How many grams of oxygen gas can be formed from the decomposition of 0.437 mol HgO?
By using the balanced chemical equation for the decomposition of mercury(II) oxide (HgO): 2 HgO -> 2 Hg + O2, we see that 1 mol of HgO produces 1 mol of O2. Therefore, 0.437 mol of HgO will produce 0.437 mol of O2. To convert mol to grams, we use the molar mass of oxygen: 32.00 g/mol. so, 0.437 mol of O2 is equivalent to 0.437 mol * 32.00 g/mol = 13.92 grams of O2.
Which must be the same when comparing 1 mol of oxygen gas O2 with 1 mol of carbon monoxide gas CO?
When comparing 1 mol of oxygen gas (O₂) with 1 mol of carbon monoxide gas (CO), the number of molecules must be the same, as both contain 1 mol. Additionally, both gases will have the same volume under standard temperature and pressure conditions, which is approximately 22.4 liters. However, their molar masses and chemical properties differ significantly.
How many moles of oxygen gas O2 needed to react with 4.00 mol of Mg?
Do you mean this reaction? 2Mg + O2 -> 2MgO 4.11 moles Mg (1 mole O2/2 mole Mg) = 2.06 moles oxygen gas consumed --------------------------------------------------
In the reaction 2H2O2-2H2O O2 if you start with 4 mol of H2O2 how many moles of O2 will you end up with?
4H2O2 --> 4H2O + 2O2 That would be 2: one mol of O2 for every 2 mols of H2O2.
What volume (in milliliters) of oxygen gas is required to react with 4.03 g of Mg at STP?
2Mg + O2 ==> 2MgO Balanced Equation4.03 g Mg x 1 mole Mg/24.3 g = 0.166 moles Mg present in 4.03 g Mg.moles O2 required = 0.166 moles Mg x 1 mole O2/2 moles Mg = 0.083 moles O2 needed.At STP 1 mole occupies 22.4 L, thusVolume of O2 required = 0.083 moles x 22.4 L/mole = 1.56 L x1000 ml/L = 1859 mlsSince 4.03 g has only 3 significant figures, the correct answer should be 1860 milliliters.
How many grams of MgO are produced when 40 grams of 02 react with Mg?
Using the balanced chemical equation: 2Mg + O2 -> 2MgO, we can see that 1 mol of O2 reacts with 2 moles of Mg to produce 2 moles of MgO. Calculate the moles of O2: 40g O2 / 32g/mol = 1.25 mol O2 From the equation, 1.25 mol O2 will produce 2.5 mol of MgO. Calculate the grams of MgO produced: 2.5 mol MgO * 40.3 g/mol = 100.75 grams MgO.
How much octane can react with 0.740 of oxygen?
1 mol of octane (C8H18) reacts with 25 mol of oxygen (O2) to produce 8 mol of CO2 and 9 mol of H2O. Therefore, 0.74 mol of oxygen can react with 0.0744 mol of octane.
How many oxygens atoms does 1 mol of O2 gas have?
Type your answer here... 2 × (6.02 × 1023)
