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What is the mass of 4.00 moles of oxygen gas?
The molar mass of oxygen gas (O2) is 32.00 g/mol. Therefore, the mass of 4.00 moles of oxygen gas is 128.00 grams.
How many grams would 2350 L of O2 gas at STP weigh?
To find the weight of 2350 L of O2 gas at STP, you would first need to calculate the moles of gas using the ideal gas law. Then, use the molar mass of O2 to convert moles to grams. The molar mass of O2 is 32 g/mol, so you would multiply the moles by 32 g/mol to find the weight in grams.
How many grams of oxygen gas can be formed from the decomposition of 0.437 mol HgO?
By using the balanced chemical equation for the decomposition of mercury(II) oxide (HgO): 2 HgO -> 2 Hg + O2, we see that 1 mol of HgO produces 1 mol of O2. Therefore, 0.437 mol of HgO will produce 0.437 mol of O2. To convert mol to grams, we use the molar mass of oxygen: 32.00 g/mol. so, 0.437 mol of O2 is equivalent to 0.437 mol * 32.00 g/mol = 13.92 grams of O2.
What is the volume of oxygen that will be used by 12g of Mg to be completely converted into MgO?
The reaction : Mg + O2-----------> MgO The balanced reaction : 2 Mg + O2-----------> 2 MgO that is 2 moles of Mg reacts with one mole of oxygen gas. moles of Mg reacted = 12 g / 24 g mol-1=0.5 mol. Thus the no. of mol of O2 reacted = 0.5 mol /2 =0.25 mol If the gas is at standard temperature and pressure, then Volume of 1 mol of O2 gas = 22.4 dm3 Volume of 0.25 mol of O2 gas = 22.4 x 0.25 dm3= 5.6 dm3 the volume of oxygen that will be used to react completely with 12 g Mg =5.6 dm3 (provided that the gas is at the standard conditions.)
How many moles in 150.0 g O2?
To find the number of moles in 150.0 g of O2, first calculate the molar mass of O2, which is 32.0 g/mol (16 g/mol for each oxygen atom). Then, divide the given mass by the molar mass to get the number of moles: 150.0 g / 32.0 g/mol = 4.69 moles of O2.
How many grams of O2 are in 50moles of the oxygen gas?
Ar of O = 16g/mol Mr of O2 = 2(16) = 32g/mol Using the formula : mass = Mr x number of moles mass = 32g/mol x 50mols = 1600g
What is the mass of 4.00 moles of oxygen gas?
The molar mass of oxygen gas (O2) is 32.00 g/mol. Therefore, the mass of 4.00 moles of oxygen gas is 128.00 grams.
What is the mass of oxygen in grams?
15.994 grams/mol, but it can rounded to 15.99 or 16.0 g/mol.
How many grams would 2350 L of O2 gas at STP weigh?
To find the weight of 2350 L of O2 gas at STP, you would first need to calculate the moles of gas using the ideal gas law. Then, use the molar mass of O2 to convert moles to grams. The molar mass of O2 is 32 g/mol, so you would multiply the moles by 32 g/mol to find the weight in grams.
How many moles of ozone O3 could be formed from 96.0g of oxygen gas O2?
Using the molar mass of oxygen (O2) which is 32 g/mol, you can calculate that you have 3 moles of oxygen gas. Since the ratio of O3 to O2 is 1:2, you would form 1.5 moles of ozone (O3) from 96.0g of O2.
Which is more heavier - hydrogen gas or oxygen gas?
Mass of Hydrogen gas:- 2g/mol Mass of Oxygen gas :- 32g/mol Therefore, Oxygen gas is more heavier
What are the masses of molecular oxygen O2 hydrogen H2 and nitrogen in grams?
The molar mass of O2 is 32 g/mol, H2 is 2 g/mol, and N2 is 28 g/mol. To calculate the mass in grams, you would multiply the molar mass by the number of moles of the substance. For example, for 1 mole of O2, the mass would be 32 grams.
How many grams of oxygen gas can be formed from the decomposition of 0.437 mol HgO?
By using the balanced chemical equation for the decomposition of mercury(II) oxide (HgO): 2 HgO -> 2 Hg + O2, we see that 1 mol of HgO produces 1 mol of O2. Therefore, 0.437 mol of HgO will produce 0.437 mol of O2. To convert mol to grams, we use the molar mass of oxygen: 32.00 g/mol. so, 0.437 mol of O2 is equivalent to 0.437 mol * 32.00 g/mol = 13.92 grams of O2.
What is the volume of oxygen that will be used by 12g of Mg to be completely converted into MgO?
The reaction : Mg + O2-----------> MgO The balanced reaction : 2 Mg + O2-----------> 2 MgO that is 2 moles of Mg reacts with one mole of oxygen gas. moles of Mg reacted = 12 g / 24 g mol-1=0.5 mol. Thus the no. of mol of O2 reacted = 0.5 mol /2 =0.25 mol If the gas is at standard temperature and pressure, then Volume of 1 mol of O2 gas = 22.4 dm3 Volume of 0.25 mol of O2 gas = 22.4 x 0.25 dm3= 5.6 dm3 the volume of oxygen that will be used to react completely with 12 g Mg =5.6 dm3 (provided that the gas is at the standard conditions.)
What is the atomic mass of gas?
The atomic mass of a gas depends on the specific element that the gas is composed of. For example, the atomic mass of oxygen gas (O2) is approximately 32 g/mol, while the atomic mass of hydrogen gas (H2) is approximately 2 g/mol.
How many moles in 150.0 g O2?
To find the number of moles in 150.0 g of O2, first calculate the molar mass of O2, which is 32.0 g/mol (16 g/mol for each oxygen atom). Then, divide the given mass by the molar mass to get the number of moles: 150.0 g / 32.0 g/mol = 4.69 moles of O2.
What mass of iron is required to react with 22.37 mol of oxygen gas?
The balanced chemical equation for the reaction between iron and oxygen is 4Fe + 3O2 -> 2Fe2O3. Using the mole ratios from the equation, for every 3 moles of O2, 4 moles of Fe are required. Therefore, to react with 22.37 mol of O2, (22.37 mol O2) x (4 mol Fe / 3 mol O2) = 29.83 mol of Fe is needed. The molar mass of Fe is approximately 55.85 g/mol, so the mass of iron required is (29.83 mol) x (55.85 g/mol) = 1666.29 g or 1.67 kg.
