4.6ms
The total displacement of the jogger can be found by adding up the individual displacements from each segment. The displacement for the first segment is (5 m/s) * (4 minutes) = 20 meters. The displacement for the second segment is (4 m/s) * (3 minutes) = 12 meters. Therefore, the total displacement is 20 meters + 12 meters = 32 meters.
To find the total displacement, we need to calculate the total distance covered in each segment. In the first segment, d1 = 5 m/s * 4 min = 120 m. In the second segment, d2 = 4 m/s * 3 min = 60 m. Thus, the total displacement is the sum of the two distances: 120 m + 60 m = 180 m.
The average jogging speed is around 5-6 miles per hour, but this can vary depending on factors such as fitness level, terrain, and distance.
No. An object is accelerating if it is changing speed or direction of travel. Since the person in question is running at a constant speed in a straight line, they are not accelerating.
Shane's mother's average speed is 6.7 mph.
4.6ms
4.60
The jogger's average speed is 6 miles per hour.
If a jogger jogs around a circular track with a diameter of 275 meters in 14 minutes his average speed (pace) is 1.0285 meters per second.
The total displacement of the jogger can be found by adding up the individual displacements from each segment. The displacement for the first segment is (5 m/s) * (4 minutes) = 20 meters. The displacement for the second segment is (4 m/s) * (3 minutes) = 12 meters. Therefore, the total displacement is 20 meters + 12 meters = 32 meters.
1.385 kilometres per hour
18.75 km / hr.
Displacemant = Velocity x Time First D1 = 5 x 4 x 60 = 1200 m Then D2 = 4 x 3 x 60 = 720 m Total displacement = D1 + D2 = 1920 m
6 km in 45 minutes = 6/45 = 0.133 km per minute.
6.4 kph
His pace is about 7.46 mph or 12 km/h
3.53 mph or 5.68 kmh speed = distance / time