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A man holds a 4.0kg steel ball in hand His arm is 70cm long and has a mass of 4.0kg What is the magnitude of the torque about his shoulder if he holds his arm straight but 50 degrees below horizontal?
The torque is calculated as the force applied multiplied by the distance from the pivot point (in this case, the shoulder) to the line of action of the force. In this scenario, the torque would be the weight of the ball (mg) multiplied by the lever arm (the horizontal distance from the shoulder to the ball). The angle below horizontal does not affect the torque in this case.
Will a vector at 45 degrees to he horizontal be larger or smaller than its horizontal and vertical components?
The magnitude of the vector at 45 degrees to the horizontal will be equal to the magnitude of its horizontal and vertical components. This is because the components are obtained by using trigonometric functions of the angle, and in this case, at 45 degrees, those functions yield the same value for both the horizontal and vertical components as the magnitude of the vector.
Where A Particle Is Projected Along A Linear Plane. The Horizontal Component Of The Velocity Is Twice The Vertical Component What Is The Initial Magnitude Of The Velocity And The Angle At Which It Is?
The initial magnitude of the velocity is sqrt(5) times the horizontal component. This results in a velocity vector that is inclined at an angle of arctan(2) ≈ 63.43 degrees with respect to the horizontal.
How can a force be resolved in to rectangular components?
You would use trigonometry for that. If, for example, you have a force of magnitude 10 at an angle of 30 degrees: * The x-component is 10 times the cosine of 30 degrees * The y-component is 10 times the sine of 30 degrees Or better yet, learn to use the polar-->rectangular conversion on your scientific calculator.
What is the magnitude and direction of the resultant force of this situation Both angles have 30N force vector one is at 34 degrees and vector two is at 76 degrees 22 degrees between the two?
To add two vectors, you add the components. The angles are specified in polar coordinates (magnitude and angle); use the same convention for both angles (for example, measure them from the x-axis counterclockwise), then use your scientific calculator to convert from polar coordinates to rectangular coordinates. Most scientific calculators have a P->R conversion. After that, you can add the components of the vectors separately. Since you want the magnitude and direction of the resultant force, you then need to convert back to polar coordinates (R->P conversion, on your calculator).
A man holds a 4.0kg steel ball in hand His arm is 70cm long and has a mass of 4.0kg What is the magnitude of the torque about his shoulder if he holds his arm straight but 50 degrees below horizontal?
The torque is calculated as the force applied multiplied by the distance from the pivot point (in this case, the shoulder) to the line of action of the force. In this scenario, the torque would be the weight of the ball (mg) multiplied by the lever arm (the horizontal distance from the shoulder to the ball). The angle below horizontal does not affect the torque in this case.
Will a vector at 45 degrees to he horizontal be larger or smaller than its horizontal and vertical components?
The magnitude of the vector at 45 degrees to the horizontal will be equal to the magnitude of its horizontal and vertical components. This is because the components are obtained by using trigonometric functions of the angle, and in this case, at 45 degrees, those functions yield the same value for both the horizontal and vertical components as the magnitude of the vector.
Where A Particle Is Projected Along A Linear Plane. The Horizontal Component Of The Velocity Is Twice The Vertical Component What Is The Initial Magnitude Of The Velocity And The Angle At Which It Is?
The initial magnitude of the velocity is sqrt(5) times the horizontal component. This results in a velocity vector that is inclined at an angle of arctan(2) ≈ 63.43 degrees with respect to the horizontal.
How do you resolve a horizontal force of 40 newtons into two perpendicular directions one of them inclines by 30 degree with the horizontal and upwards?
-- The component that's inclined 30 degrees above the horizontal is[ 20 sqrt(3) ] = about 34.641 newtons. (rounded)-- The other component is inclined 60 degrees below the horizontal,and its magnitude is 20 newtons.
What is the optimal range of motion for shoulder flexion, specifically in relation to achieving 120 degrees of movement?
The optimal range of motion for shoulder flexion to achieve 120 degrees of movement is typically between 0 to 180 degrees. This means that the shoulder should be able to move from a straight position (0 degrees) to a position where the arm is raised above the head (180 degrees).
Can a triangle have a straight angle?
If you mean by straight angel an angel of magnitude 180 degrees, then the answer is no. The sum of the three interior triangle angels is 180 and not only a single angel.
What is the meaning of vertical level?
Perpendicular or 90 degrees to level (horizontal level)... In other words, straight up and down.
What does 160 degree angles look like?
An obtuse angle is an angle between 90 degrees and 180 degrees. A 180 degree angle is a straight horizontal line. So you can imagine that a 160 degree angle is almost but not quite horizontal.
How can a force be resolved in to rectangular components?
You would use trigonometry for that. If, for example, you have a force of magnitude 10 at an angle of 30 degrees: * The x-component is 10 times the cosine of 30 degrees * The y-component is 10 times the sine of 30 degrees Or better yet, learn to use the polar-->rectangular conversion on your scientific calculator.
What is the range of motion for horizontal adduction of the shoulder?
The range of motion for horizontal adduction of the shoulder is typically around 100-120 degrees, depending on individual flexibility and strength. This movement involves bringing the arm across the front of the body towards the opposite shoulder. It is important to perform this motion within a pain-free range to prevent injury.
What are not horizontal and vertical lines?
Any line that is not running exactly straight up and down is not vertical. Any line that is not running exactly flat, left to right is not horizontal. Vertical and horizontal lines are always at 90 degrees to each other.
What a step graph?
A graph which consists of short straight lines which keep changing direction. Example : a graph line which is inclined at say, 30 degrees to a horizontal, then changes direction instantly to a line which is say, inclined at 60 degrees to the horizontal , etc. If the shape of a graph is not a series of straight lines joined to each other, then it is not a step graph.
