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1/2mvi^2+mghi=1/2mvf^2+mghf is the equation.

M can be cancelled out.

Substitute quantities.

Assume vi is 0.

Gravity is 9.8.

Vf is 1.9.

Hf is 0

1/2x0+9.8hi=1/2(1.9^2)+9.8x0

9.8hi=1.81

Hi=.185m

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Q: A pendulum bob is released from some initial height such that the speed of the bob at the bottom of the swing is 1.9 meters per second. What is the initial height of the bob?
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What is the initial arclength of a pendulum when you know the length and mass and max velocity and initial height of the pendulum?

If you know the initial height and the length of the pendulum, then you have no use for the mass or the velocity. You already have the radius of a circle, and an arc for which you know the height of both ends. You can easily calculate the arc-length from these. And by the way . . . it'll be the same regardless of the mass or the max velocity. They don't matter.


How many swings a pendulum makes in a second?

That depends on a number of different variables and therefore it cannot be concluded here. It depends on the mass of the object being swung as well as the initial conditions of this object such as the height it is released or the initial velocity by which it was flung.


Why does a pendulum in motion never swing to a greater height than it started?

This is a conservation of energy problem. When the pendulum starts out, it has gravitational potential energy; at the bottom of the swing, all of that has been converted to kinetic energy, and when it swings back up, back to gravitational potential energy (which is why speed is greatest at the bottom of the pendulum); in other words, there has to be the same amount of energy (PEgravitational = mass*gravity*height), where mass and gravity are constant.


Does the height of release affect the swing of a pendulum?

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Is the ending and starting height of the pendulum exactly the same?

No, the swing of the pendulum will never carry it back quite as high as it was when it started. The pendulum must work against air resistance, and so a little bit of momentum is lost with every swing. Even if the pendulum operated in a vacuum, there would still be some tiny amount of friction at the point where the pendulum is attached to its frame. The swing of a pendulum is never 100% efficient. So the pendulum will run down.

Related questions

What is the initial arclength of a pendulum when you know the length and mass and max velocity and initial height of the pendulum?

If you know the initial height and the length of the pendulum, then you have no use for the mass or the velocity. You already have the radius of a circle, and an arc for which you know the height of both ends. You can easily calculate the arc-length from these. And by the way . . . it'll be the same regardless of the mass or the max velocity. They don't matter.


How many swings a pendulum makes in a second?

That depends on a number of different variables and therefore it cannot be concluded here. It depends on the mass of the object being swung as well as the initial conditions of this object such as the height it is released or the initial velocity by which it was flung.


How does height affect the period of a pendulum?

Height does not affect the period of a pendulum.


Why does a pendulum in motion never swing to a greater height than it started?

This is a conservation of energy problem. When the pendulum starts out, it has gravitational potential energy; at the bottom of the swing, all of that has been converted to kinetic energy, and when it swings back up, back to gravitational potential energy (which is why speed is greatest at the bottom of the pendulum); in other words, there has to be the same amount of energy (PEgravitational = mass*gravity*height), where mass and gravity are constant.


Does the height of release affect the swing of a pendulum?

no.


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