1/2mvi^2+mghi=1/2mvf^2+mghf is the equation.
M can be cancelled out.
Substitute quantities.
Assume vi is 0.
Gravity is 9.8.
Vf is 1.9.
Hf is 0
1/2x0+9.8hi=1/2(1.9^2)+9.8x0
9.8hi=1.81
Hi=.185m
If you know the initial height and the length of the pendulum, then you have no use for the mass or the velocity. You already have the radius of a circle, and an arc for which you know the height of both ends. You can easily calculate the arc-length from these. And by the way . . . it'll be the same regardless of the mass or the max velocity. They don't matter.
That depends on a number of different variables and therefore it cannot be concluded here. It depends on the mass of the object being swung as well as the initial conditions of this object such as the height it is released or the initial velocity by which it was flung.
This is a conservation of energy problem. When the pendulum starts out, it has gravitational potential energy; at the bottom of the swing, all of that has been converted to kinetic energy, and when it swings back up, back to gravitational potential energy (which is why speed is greatest at the bottom of the pendulum); in other words, there has to be the same amount of energy (PEgravitational = mass*gravity*height), where mass and gravity are constant.
no.
No, the swing of the pendulum will never carry it back quite as high as it was when it started. The pendulum must work against air resistance, and so a little bit of momentum is lost with every swing. Even if the pendulum operated in a vacuum, there would still be some tiny amount of friction at the point where the pendulum is attached to its frame. The swing of a pendulum is never 100% efficient. So the pendulum will run down.
If you know the initial height and the length of the pendulum, then you have no use for the mass or the velocity. You already have the radius of a circle, and an arc for which you know the height of both ends. You can easily calculate the arc-length from these. And by the way . . . it'll be the same regardless of the mass or the max velocity. They don't matter.
That depends on a number of different variables and therefore it cannot be concluded here. It depends on the mass of the object being swung as well as the initial conditions of this object such as the height it is released or the initial velocity by which it was flung.
Height does not affect the period of a pendulum.
This is a conservation of energy problem. When the pendulum starts out, it has gravitational potential energy; at the bottom of the swing, all of that has been converted to kinetic energy, and when it swings back up, back to gravitational potential energy (which is why speed is greatest at the bottom of the pendulum); in other words, there has to be the same amount of energy (PEgravitational = mass*gravity*height), where mass and gravity are constant.
no.
23 sec
height=acceletation(t^2) + velocity(t) + initial height take (T final - T initial) /2 and place it in for time and there you go
there are three, height, weight, and length
Our Physics class calculated that the height of the dome inside the cathedral is approximately 16m. We used the relationship between the period of a pendulum (incense thurible) and the length of the pendulum.
As the length of a pendulum increase the time period increases whereby its speed decreases and thus the momentum decrease.
No, the swing of the pendulum will never carry it back quite as high as it was when it started. The pendulum must work against air resistance, and so a little bit of momentum is lost with every swing. Even if the pendulum operated in a vacuum, there would still be some tiny amount of friction at the point where the pendulum is attached to its frame. The swing of a pendulum is never 100% efficient. So the pendulum will run down.
4h