Simply use the expression v = gt
g = 9.8 m/s^2 and t given as 4.5 s
So velocity with which the penny hits the ground will be 44.1 m/s
The velocity of the penny as it hits the ground can be calculated using the equation: velocity = distance/time. Assuming the penny falls vertically, if we take the distance it falls to be 9.8 m/s^2 x (4.5 s)^2 / 2 ≈ 99.22 meters and the time is 4.5 seconds, the velocity would be 99.22 meters / 4.5 seconds = 22.04 m/s.
A penny dropped from the top of a skyscraper would reach the ground in approximately 9.2 seconds. A passerby on the sidewalk below would have less than 9 seconds to move out of the way once they see the penny falling.
As a dropped penny falls toward the ground, potential energy is converted into kinetic energy. The higher the penny is dropped from, the more potential energy it has, which is converted into kinetic energy as it accelerates downwards due to gravity.
I say NO. If you mean it is dropped and falls vertically. Discover Channel's "Myth Busters" tried to determine if a bullet would kill you if it was fired directly vertical and falls on its own. The bullet or penny would fall at terminal velocity which is about 120mph. However, they will tumble which slows them down more. This velocity and their mass is not enough to kill you.
If the penny is in a vaccum, the penny has no terminal velocity because verminal velocity is when the resistance against the falling penny is equal to the force of gravity. So if it is in a vaccum, it has no forces resisting the fall, and it has no terminal velocity.
The velocity of the penny as it hits the ground can be calculated using the equation: velocity = distance/time. Assuming the penny falls vertically, if we take the distance it falls to be 9.8 m/s^2 x (4.5 s)^2 / 2 ≈ 99.22 meters and the time is 4.5 seconds, the velocity would be 99.22 meters / 4.5 seconds = 22.04 m/s.
it would be 7
A penny dropped from the top of a skyscraper would reach the ground in approximately 9.2 seconds. A passerby on the sidewalk below would have less than 9 seconds to move out of the way once they see the penny falling.
112/96 = 1. 16666-seconds
1second
As a dropped penny falls toward the ground, potential energy is converted into kinetic energy. The higher the penny is dropped from, the more potential energy it has, which is converted into kinetic energy as it accelerates downwards due to gravity.
I say NO. If you mean it is dropped and falls vertically. Discover Channel's "Myth Busters" tried to determine if a bullet would kill you if it was fired directly vertical and falls on its own. The bullet or penny would fall at terminal velocity which is about 120mph. However, they will tumble which slows them down more. This velocity and their mass is not enough to kill you.
If a penny and a text book were dropped in a vacuum then they will both hit the ground at the same time. This refers to Newton's laws. If they are dropped at the same time on earth then the text book would hit the ground first.
If you drop a penny off the Empire State Building, it falls at its own terminal velocity after falling about 200+ metres (that's a guess but it's around 200). A penny's terminal velocity is roughly half of a falling person's terminal velocity. A falling skydiver will reach a maximum of around 130mph, so a penny will fall at approximately 65mph.
Yes
The penny drop a height after 1 second penny is on the ground
The kinetic energy of the penny can be calculated using the formula: KE = 0.5 * m * v^2, where m is the mass and v is the velocity. First, calculate the velocity using the height dropped formula: v = sqrt(2 * g * h), where g is the acceleration due to gravity. Then, substitute the values to find the kinetic energy.