0
What else can I help you with?
Why when you use parachute the acceleration decrease?
when we use parachute, the wide surface area can decrease the velocity of the fallen object. thus, the drag force will also decrease. consequently, acceleration will be zero when the velocity is constant. finally, the object can land more safely without huge impact.
What is the speed of a rock initially at rest that has fallen 66m near the earths surface?
Assuming the acceleration due to gravity is 9.81 m/s^2, the speed of the rock can be calculated using the equation v = sqrt(2 * g * h), where v is the final velocity, g is the acceleration due to gravity, and h is the height fallen. Plugging in the values, v = sqrt(2 * 9.81 * 66) ≈ 34.4 m/s.
If i throw a ball downward from a window at a speed of 2.5 ms How fast will it be moving when it hits the sidewalk 3.0 m below?
This would be the simple answer, ignoring air resistance, wind, and other such incooperative forces. First working out the vertical component of velocity when it hits the floor: final velocity (v) = ? Initial velocity (u) = 0 Displacement (s) = 3 Accelleration (a) = g; taken to be 9.81 Using the equationof linear motion v2 = u2 + 2as v2 = 0 + (2 * 9.81 * 3) v2 = 58.86 v = 7.672 Now we know that the horizontal component of velocity will be 2.5 ms-1 (ignoring air resistance) so now we have to find out the velocity of the ball when it hits the floor, if it is travelling at a velocity with a downwards vertical component of 7.672ms-1 and a horizontal component of 2.5ms-1 2.52 + 7.6722 = 65.1095 Square rooting that... Velocity = 8.069ms-1
A ball of mass m rolls off a cliff of height h with a horizontal velocity v it reaches the ground with vertical speed of?
If one assumes air resistance to be negligible, then: final velocity = sqrt( g * 2 * h ) where g is 9.8 metres per second per second. The quantities v and m do not matter, because gravitational acceleration does not depend on mass (all objects fall at the same rate) and because the horizontal velocity is independent of the vertical velocity.
If a freely falling object is equipped with a odometer Would the readings of distance falling each second indicate equal or unequal distances of fall for successive seconds?
It depends on how heavy the rock is. The heavier it is the faster it will fall. No. Acceleration due to gravity is independent of weight. Galileo proved as much. acceleration due to gravity is dependent on latitude but is always near 10m/s2
What is the velocity of a dropped object after it has fallen for 3.0?
The final velocity of a dropped object can be calculated using the equation v = gt, where v is the final velocity, g is the acceleration due to gravity (approximately 9.81 m/s^2), and t is the time the object has fallen. Plugging in the values, the final velocity of a dropped object after falling for 3.0 seconds would be 29.43 m/s.
Lucille knocks her textbook off her desk After it has fallen for 2 seconds what is its velocity?
16.4
What is the velocity of a book after it has fallen for 2 seconds?
The velocity of a falling book after 2 seconds is approximately 19.6 m/s. This is assuming the book is in free fall under the acceleration due to gravity (9.8 m/s^2).
After something has fallen for 4 seconds what is its velocity?
If you assume a gravity of 9.8, that would be 4 x 9.8 (answer in meter/second). If there is air resistance, the speed will be less than that.
What is the duration of Fallen Art?
The duration of Fallen Art is 360.0 seconds.
What is the duration of Reign of the Fallen?
The duration of Reign of the Fallen is 3300.0 seconds.
Can you find repack in a sentence?
After he dropped his case and things had fallen out, he had to repack them.
What is the duration of Fallen Angels TV series?
The duration of Fallen Angels - TV series - is 1800.0 seconds.
Do MacBook Airs break easily if dropped?
If fallen on the top or screen, mostlikely
How far will a rubber ball fall in ten seconds?
The distance a rubber ball falls in 10 seconds will depend on the height from which it is dropped and the acceleration due to gravity. On Earth, neglecting air resistance, the general equation to calculate the distance fallen is: distance = 0.5 * acceleration due to gravity * time^2.
What is the velocity of a 50 gram egg dropped 3 meters off the ground right before it hits the ground?
Ignoring the effects of air resistance, the velocity of any object dropped near the surface of the Earth is 29.42 meters (96.53 feet) per second, directed downward, after it has fallen 3 meters. If you're working with situations and asking questions like this one, then you're supposed to know by now that the mass or weight of the object makes no difference. If you can eliminate air resistance, then the answer is the same for a feather, a bowling ball, and a battleship.
How do you find the velocity of an object that has fallen 10 m?
Assuming the the object was dropped and is relatively close to the earth's surface; then we can say that since: distance=(1/2)(acceleration)(time)2 ; 10m=(1/2)(9.8)(time)2 ; then the time spent falling is apprx. 1.429s, multiplied by the acceleration (9.8 m/s2) gives us a velocity of apprx. 14.00 m/s
