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The distance traveled by the man is equal to the perimeter of the track, which is 2*(length + breadth) = 2*(40 + 30) = 2*70 = 140m. The magnitude of displacement is the shortest distance between the initial and final positions, which can be found using the Pythagorean theorem as sqrt(40^2 + 30^2) = sqrt(1600 + 900) = sqrt(2500) = 50m.

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A rectangular track is 40m long and 30m broad a man starts walking from one corner of the track and reaches the opposite corner find the distance travelled and the magnitude of displacement?

The distance traveled by the man is equal to the perimeter of the rectangle which is 40m + 30m + 40m + 30m = 140m. The magnitude of displacement is the shortest distance between the initial and final positions, which is the diagonal of the rectangle. Using the Pythagorean theorem, the diagonal is √(40^2 + 30^2) = √(1600 + 900) = √2500 = 50m.


When displacement have the opposite derection what do you do to determine the magnitude?

Displacement is a vector quantity. Hence, while finding resultant vector we need to use vector algebra and the properties of vectors. If the 2 displacement vectore are in opposite directions,it means that the angle between them is 180degrees and hence we can directly subtract them.


Can distance and displacement be negative?

Yes it can. If distance and displacement is positive then it means it's going forwards. If you get a distance or displacement that is negative then means it's going the other direction, backwards.


Can distance be negative in physics?

No. Distance is never negative, and total distance travelled doesn't decrease during a trip. The distance from A to B is the same as the distance from B to A. Displacement, on the other hand, can be negative, and can decrease during a trip. The displacement from A to B is the same magnitude, but opposite sign, as the displacement from B to A. An example would be if you went from your home to a friend's house 1 mile to the east. After you reach your friend's house, you have travelled a distance of 1 mile and your displacement from your starting position is 1 mile. When you come back home from your friends house, you travel a distance of 1 more mile. Your total distance travelled is now 2 miles, but your displacement from your starting location is zero (because you are back where you started.) Distance does not have direction, and is always positive (or zero). Displacement has direction, and can be negative, positive, or zero.


How do you find displacement of negative velocity time graph?

To find the displacement from a negative velocity-time graph, you need to calculate the area under the curve for the portion representing displacement. If the velocity is negative, the displacement will be in the opposite direction. The magnitude of the displacement is equal to the absolute value of the area under the curve.

Related Questions

A rectangular track is 40m long and 30m broad a man starts walking from one corner of the track and reaches the opposite corner find the distance travelled and the magnitude of displacement?

The distance traveled by the man is equal to the perimeter of the rectangle which is 40m + 30m + 40m + 30m = 140m. The magnitude of displacement is the shortest distance between the initial and final positions, which is the diagonal of the rectangle. Using the Pythagorean theorem, the diagonal is √(40^2 + 30^2) = √(1600 + 900) = √2500 = 50m.


When displacement have the opposite derection what do you do to determine the magnitude?

Displacement is a vector quantity. Hence, while finding resultant vector we need to use vector algebra and the properties of vectors. If the 2 displacement vectore are in opposite directions,it means that the angle between them is 180degrees and hence we can directly subtract them.


Can distance and displacement be negative?

Yes it can. If distance and displacement is positive then it means it's going forwards. If you get a distance or displacement that is negative then means it's going the other direction, backwards.


What is the difference between distance an displacement?

A distance is the length of the straight line path between 2 points. This is also known as a scalar value as it has a magnitude but no direction. A displacement is the distance and the direction between one point and another. This is also known as a vector as it has magnitude and direction as well. Note that the distance between two points, say, point A and point B is the same as the distance from point B to point A. It remains the same value regardless of the direction of travel. On the other hand, if a displacement between point A and point B was 1 mile North, it cannot be reversed. The displacement between point B and point A is 1 mile South - the same distance but an opposite direction.


Can distance be negative in physics?

No. Distance is never negative, and total distance travelled doesn't decrease during a trip. The distance from A to B is the same as the distance from B to A. Displacement, on the other hand, can be negative, and can decrease during a trip. The displacement from A to B is the same magnitude, but opposite sign, as the displacement from B to A. An example would be if you went from your home to a friend's house 1 mile to the east. After you reach your friend's house, you have travelled a distance of 1 mile and your displacement from your starting position is 1 mile. When you come back home from your friends house, you travel a distance of 1 more mile. Your total distance travelled is now 2 miles, but your displacement from your starting location is zero (because you are back where you started.) Distance does not have direction, and is always positive (or zero). Displacement has direction, and can be negative, positive, or zero.


Can distance ever be negative?

No. Distance is never negative, and total distance travelled doesn't decrease during a trip. The distance from A to B is the same as the distance from B to A. Displacement, on the other hand, can be negative, and can decrease during a trip. The displacement from A to B is the same magnitude, but opposite sign, as the displacement from B to A. An example would be if you went from your home to a friend's house 1 mile to the east. After you reach your friend's house, you have travelled a distance of 1 mile and your displacement from your starting position is 1 mile. When you come back home from your friends house, you travel a distance of 1 more mile. Your total distance travelled is now 2 miles, but your displacement from your starting location is zero (because you are back where you started.)


How do you find displacement of negative velocity time graph?

To find the displacement from a negative velocity-time graph, you need to calculate the area under the curve for the portion representing displacement. If the velocity is negative, the displacement will be in the opposite direction. The magnitude of the displacement is equal to the absolute value of the area under the curve.


When do two vectors cancel each other?

When they have the same magnitude, but opposite directions.When they have the same magnitude, but opposite directions.When they have the same magnitude, but opposite directions.When they have the same magnitude, but opposite directions.


How are displacements that occur in opposite directions combined?

Displacements in opposite directions are combined by using vector addition. If the displacements have the same magnitude, they cancel each other out. If they have different magnitudes, the combined displacement is the difference between the two displacements in the direction of the larger displacement.


Why the ratio of displacement to distance is never greater than 1?

The technical answer is that displacement is the vector sum of the distances. An example to illustrate the difference in less technical terms, distance travelled in one direction added to the same distance in the opposite direction will result in the total distance being twice the distance of each leg but the total displacement is 0.


What is the result of two displacment vectors having opposite directions?

It is a displacement equal in magnitude to the difference between the two vectors, and in the direction of the larger vector.


What is the magnitude of the displacement of a car that travels half a lap along a circle that has a radius of 175 m?

Displacement is the straight line distance between two points. If the two points are a half a lap apart on a circular path then the straight line distance is the diameter of the circle; 350 m. What that means is that displacement describes only the relationship between end position and starting position, so the car stops at a point on the opposite side of the circle, 350m from the start. Displacement is not necessarily distance traveled. If the car had gone completely around the circle and stopped where it started, the displacement would be zero, even though it has traveled nearly 1100 m.