They will arrive at the floor together (assuming the floor is horizontal). The reason is that both the initial vertical component of the speed, and the vertical acceleration, are the same.
No, this statement is not true. When a rifle is fired horizontally, the bullet immediately begins to drop due to gravity as soon as it leaves the barrel. The rate of drop will depend on the muzzle velocity of the bullet and the distance it has traveled.
When we roll a barrel on the road, rolling friction acts in the direction opposite to the direction of rolling. In case of pulling, kinetic friction acts opposite to the direction in which the barrel moves. The coefficient of rolling friction is almost always less than the coefficient of kinetic friction. So therefore, in layman's terms, rolling friction is less than kinetic friction, therefore less resistance is faced by the barrel while rolling.
When a gun is fired, the force that affects the bullet as it leaves the barrel and travels through the air is the explosive force generated by the gunpowder igniting and rapidly expanding gases, propelling the bullet forward. This force propels the bullet through the barrel and imparts momentum to it, allowing it to overcome air resistance and travel towards its target.
No- or minimal at best. Acceleration of the bullet comes from gas expanding inside the barrel, pushing the bullet. Once it leaves the barrel, (or within a VERY short distance) gas is no longer pushing, and acceleration stops, and bullet begins to slow from air resistance.
The instant the bullet leaves the barrel it is subject to gravity. If the barrel is lined up exactly on a distant target, the bullet will fall short. The longer the distance, the more elevation is required. The same applies to a football, baseball, or basketball. When the person you are throwing it to is far away, you throw it higher so that it will reach them. With a bullet the principle is the same. You must also allow for wind
No. Assuming the barrel is level (defined as perpendicular to the pull of gravity) then the bullet will leave the barrel horizontally and immediately begin to fall, like any other object subject to gravity. There are aerodynamic forces from air resistance, but these do not impart lift to the bullet. Often the gun recoils (per Newton's laws) in such a way as to raise the barrel after the bullet has fired.
Projectiles begin to drop as soon as they exit the barrel.
No, this statement is not true. When a rifle is fired horizontally, the bullet immediately begins to drop due to gravity as soon as it leaves the barrel. The rate of drop will depend on the muzzle velocity of the bullet and the distance it has traveled.
Rifling imparts spin that stabilizes the projectile. The rate or "twist" determines how much
When we roll a barrel on the road, rolling friction acts in the direction opposite to the direction of rolling. In case of pulling, kinetic friction acts opposite to the direction in which the barrel moves. The coefficient of rolling friction is almost always less than the coefficient of kinetic friction. So therefore, in layman's terms, rolling friction is less than kinetic friction, therefore less resistance is faced by the barrel while rolling.
Towards and ABOVE the target. Gravity will cause the bullet to drop, so point of aim must be above the target.
When a gun is fired, the force that affects the bullet as it leaves the barrel and travels through the air is the explosive force generated by the gunpowder igniting and rapidly expanding gases, propelling the bullet forward. This force propels the bullet through the barrel and imparts momentum to it, allowing it to overcome air resistance and travel towards its target.
No- or minimal at best. Acceleration of the bullet comes from gas expanding inside the barrel, pushing the bullet. Once it leaves the barrel, (or within a VERY short distance) gas is no longer pushing, and acceleration stops, and bullet begins to slow from air resistance.
There is an excellent article at the link below to explain the choke process for shotguns.
You're sure this isn't a reed issue? If so, have you tried different mouthpieces? Changing the barrel can have an effect too. That's about it.
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There is a water analogy that might help. Imagine a large barrel full of water. The volume of the water (the water in the barrel is constantly replenished) represents volts and will stay constant (say 120 volts). Volts is essentially a potential. Now if you have a faucet at the lowest part of the barrel this represents a resistance to the water to escape from the barrel. Now Ohm's Law states that Voltage = Current x Resistance. With the faucet closed you have infinite resistance, so you have no current flowing. If you open the faucet just a little (large amount of resistance still, say 100 ohms) then a small stream of water will escape the barrel, the flow of water out of the barrel is the current (I=E/R=120/100=1.2 amps). If you had a water wheel that the stream could fall on it would turn and could do work, since it is a small stream it is doing a small amount of work (W=ExI=120x1.2=144 watts). If you open the faucet all the way the water will come out faster since there is less resistance (I=E/R=120/10=10 amps) and can do more work (W=ExI=120x10=1,200 watts).