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A rocket accelerates at a rate of 30 m/s¶ for 2 minutes. What is its change in velocity?

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Heaven Wisoky

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2y ago
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Deliylah Navas

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1y ago
i dont get it
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15y ago

Errata: 30 m.s-1 is an expression of velocity rather than acceleration. Following answer assumes 30 m.s-2 From Newton's III, we know that the force exerted by the engine on the space-shuttle will equal that force exerted by the shuttle on the engine. The shuttle's mass gives it inertia, which means it has a resistance to velocity. Newton's II law (a = F / m) explains that acceleration is inversely proportional to mass, and proportional to force. This leads to the F = m x a statement of the law. Hence; the force *exerted* by the rocket *on* the shuttle, provided that the shuttle is 2x10^6 kg and the acceleration (rate of change of velocity) is 30 m.s-2, is simply equal to: F = m x a F = (2x10^6)*(30) F = 60 000 000 Newtons = 6x10^7 N

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14y ago

Well, 30 m per second squared means that for every second the change in velocity delta v is 30 mps. Thus, in two minutes, or 120 seconds, the change is 30*120 = 3600 mps.

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Q: A rocket accelerates at a rate of ms for 2 minutes what is it change in velocity?
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