A rocket accelerates at a rate of 30 m/s¶ for 2 minutes. What is its change in velocity?
Errata: 30 m.s-1 is an expression of velocity rather than acceleration. Following answer assumes 30 m.s-2 From Newton's III, we know that the force exerted by the engine on the space-shuttle will equal that force exerted by the shuttle on the engine. The shuttle's mass gives it inertia, which means it has a resistance to velocity. Newton's II law (a = F / m) explains that acceleration is inversely proportional to mass, and proportional to force. This leads to the F = m x a statement of the law. Hence; the force *exerted* by the rocket *on* the shuttle, provided that the shuttle is 2x10^6 kg and the acceleration (rate of change of velocity) is 30 m.s-2, is simply equal to: F = m x a F = (2x10^6)*(30) F = 60 000 000 Newtons = 6x10^7 N
Well, 30 m per second squared means that for every second the change in velocity delta v is 30 mps. Thus, in two minutes, or 120 seconds, the change is 30*120 = 3600 mps.
The combustion of rocket fuel ejects a mass of material at high velocity. In accordance with Newton's third law, the momentum of the ejecta generates an equal and opposite reaction - which propels the rocket forward.
3000m/s
initial velocity would be ZERO before launch. To calculate the velocity you would need to hit that target at that distance you would need to know the mass of the rocket and the angle of launch or trajectory simplifying it
A model rocket reaches maximum velocity at the point where the thrust from the engine matches the drag from the air, or the point where the thrust goes to zero when the fuel burns out, whichever comes first.
It could - but that's not the idea (except from start to whatever velocity you select). Since the rocket must reach either escape or orbital velocity (25000 mph or 18000 mph), if you could start off with that speed, the sudden jerk would tear it apart.
Thrust.
The products of the burning fuel are ejected from the rocket at high velocity. In accordance with Newton 's Third Law, this action generates an equal and opposite reaction on the rocket. The forward forward force acting on the rocket accelerates it.
The combustion of rocket fuel ejects a mass of material at high velocity. In accordance with Newton's third law, the momentum of the ejecta generates an equal and opposite reaction - which propels the rocket forward.
If we start from newtons third law, we can get the idea of action and reaction is equal and opposite It is its' fuel ejection that enables the rocket to fly forward. P=MV But here mass is decreasing due to the consumption of fuel thus, we are now flying at P= (M-m)V WHERE M grater than (M-m) hence the rocket clearly is moving at a constantly decreasing mass with constant velocity. therefore it clearly accelerates as time goes. Samuel
Effective jet velocity of a rocket is the increased velocity of a rocket in a short span of time. It is achieved with the use of either solid or liquid propellants.Ê
This is possible via the conservation of momentum. A rocket ejects matter from its back and this matter carries momentum. To conserve momentum the rocket must gain an equal amount of momentum in the opposite direction. Since momentum is related to velocity this causes the rocket to move. This is basically an application of Newton's third law. You might have been confused with the situation in air. For example an airplane moves through air by pushing air past it (using its propeller). This accelerates the air, and thus increases its momentum. The airplane must therefore gain momentum in the opposite direction, and accelerates itself as well. The only difference between the airplane and the rocket is that the rocket carries the stuff it accelerates (and ejects) while the airplane can use the air that is already present all around it. Note that while this is the basic explanation, the situation with the rocket is made somewhat more complicated by the fact that as the rocket loses fuel it also loses momentum because momentum is velocity times mass and the lost fuel lowers the mass of the rocket. You might want to look up Tsiolkovsky's rocket equation if you want more information.
Rockets are convenient for space travel. Aircraft use the air to hold them up, but spacecraft travel beyond the Earth's atmosphere.
Escape velocity.
By expelling hot gasses extremely fast from the rocket nozzle. Due to the conservation of momentum, expelling mass at high velocity causes the rocket to gain momentum and therefore velocity.
no
The stages of a rocket going into space: The first stage of a rocket is used to acquire the acceleration of a rocket. When the fuel of the first stage is exhausted ,it detaches from the rockets and drops off. The velocity at this stage becomes the initial velocity of the second stage .Now the second stage is ignited ,the rocket gains acceleration and it's velocity foes on increasing . The removal of the surplus mass contained in the first stage helps in attaining the higher velocity .When the fuel of the second stage is exhausted ,it too detached from the rocket .Finally at the third stage , the rocket starts off with the required velocity.
surely a rocket or artificial satellite can get out with help of escape velocity....