The speed of ball hitting the ground doesn't depends on the weight of the body(Newtons law).
The formula to be used here is:
v^2 -u^2 =2*a*s
where v= final velocity
u = initial velocity
a= acceleration (here gravitational force = 9.8m/sec^2)
s = distance
So (here u = 0)
v^2 = 2*9.8*15.2
v = 17.26m/sec
Still accelerating til it hits earth. ====================================== The height from which she dropped the ball is irrelevant. In any case, the ball was most likely moving at the greatest speed just as it hit the ground. The answer to the question is: zero.
The time it takes for a ball to hit the ground when dropped from a height can be calculated using the equation: t = √(2h/g), where h is the height (443 meters) and g is the acceleration due to gravity (9.81 m/s²). Solving for t gives a time of approximately 9 seconds.
The acceleration of an object dropped from a height of 10 meters is approximately 9.81 m/s2.
Ignoring any effects due to air resistance, the speed of the stone is zero at the instant it's dropped, and increases steadily to 78.98 meters per second when it hits the ground. The velocity is directed downward throughout the experiment.
If dropped from the same height (a few meters), they would appear to hit the ground at the same time, according to the experiments of Galileo. However, this neglects air resistance on the basketball, which will slow it down more and cause it to hit the ground later (very slightly later). The baseball, which has a smaller area and therefore less air resistance, will hit the ground first.
19.6 meters / 64.4 ft
Still accelerating til it hits earth. ====================================== The height from which she dropped the ball is irrelevant. In any case, the ball was most likely moving at the greatest speed just as it hit the ground. The answer to the question is: zero.
The time it takes for a ball to hit the ground when dropped from a height can be calculated using the equation: t = √(2h/g), where h is the height (443 meters) and g is the acceleration due to gravity (9.81 m/s²). Solving for t gives a time of approximately 9 seconds.
The acceleration of an object dropped from a height of 10 meters is approximately 9.81 m/s2.
The time it takes for a volleyball to hit the ground when dropped from a height depends on the height it falls from. Using the formula for free fall ( t = \sqrt{\frac{2h}{g}} ), where ( h ) is the height in meters and ( g ) is the acceleration due to gravity (approximately ( 9.81 , m/s^2 )), you can calculate the time. For example, if dropped from 2 meters, it would take about 0.64 seconds to hit the ground.
Using this basic formula V= √2*h*g. H represents the height from which the object is dropped to the ground in meters. G represents the pull of gravity.
Ignoring any effects due to air resistance, the speed of the stone is zero at the instant it's dropped, and increases steadily to 78.98 meters per second when it hits the ground. The velocity is directed downward throughout the experiment.
3 ft
To determine the time it takes for a ball to hit the ground when dropped from a height of 30 meters, we can use the formula for free fall: ( h = \frac{1}{2} g t^2 ), where ( h ) is the height (30 meters), ( g ) is the acceleration due to gravity (approximately 9.81 m/s²), and ( t ) is the time in seconds. Rearranging the formula gives ( t = \sqrt{\frac{2h}{g}} ). Plugging in the values, we find ( t = \sqrt{\frac{2 \times 30}{9.81}} \approx 2.47 ) seconds. Thus, the ball will hit the ground after approximately 2.47 seconds.
If dropped from the same height (a few meters), they would appear to hit the ground at the same time, according to the experiments of Galileo. However, this neglects air resistance on the basketball, which will slow it down more and cause it to hit the ground later (very slightly later). The baseball, which has a smaller area and therefore less air resistance, will hit the ground first.
If air resistance can be ignored, the acceleration is 9.82 meters per second square. Note that to get this result, neither the mass of the book, nor the height from which it is dropped, is relevant.If air resistance can be ignored, the acceleration is 9.82 meters per second square. Note that to get this result, neither the mass of the book, nor the height from which it is dropped, is relevant.If air resistance can be ignored, the acceleration is 9.82 meters per second square. Note that to get this result, neither the mass of the book, nor the height from which it is dropped, is relevant.If air resistance can be ignored, the acceleration is 9.82 meters per second square. Note that to get this result, neither the mass of the book, nor the height from which it is dropped, is relevant.
Both weights will fall at the same rate due to gravity. The acceleration due to gravity is constant regardless of the mass of the object, so both weights will reach the ground at the same time when dropped from the same height.