im guessing this is homework huh?
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
The initial velocity is sqrt(5) times the vertical component, and its angle relative to the horizontal direction, is 0.46 radians (26.6 degrees).
The horizontal velocity of the projectile (and the air resistance if known) will determine the horizontal distance traveled and the time required.
It depends because horizontal velocity does not affect vertical velocity at all! Example: If you took a bullet and shot it out of a gun at a perfectly horizontal angle (0 or 180 degrees) and dropped another bullet from the same height of the gun barrel, both bullets would hit the ground at the same time.
Ignoring air resistance, the horizontal component of velocity has no connection with, and no effect on, the vertical component. Two bodies that leave the top of the building simultaneously with the same vertical velocity hit the ground at the same time, regardless of their horizontal velocities or their masses. That's the same as saying that a bullet fired horizontally from a gun and a bullet or a stone dropped from the gun's muzzle at the same instant hit the ground at the same instant. Strange but true.
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
initial velocity, angle of launch, height above ground When a projectile is launched you can calculate how far it travels horizontally if you know the height above ground it was launched from, initial velocity and the angle it was launched at. 1) Determine how long it will be in the air based on how far it has to fall (this is why you need the height above ground). 2) Use your initial velocity to determine the horizontal component of velocity 3) distance travelled horizontally = time in air (part 1) x horizontal velocity (part 2)
The initial velocity is sqrt(5) times the vertical component, and its angle relative to the horizontal direction, is 0.46 radians (26.6 degrees).
The horizontal velocity of the projectile (and the air resistance if known) will determine the horizontal distance traveled and the time required.
It depends because horizontal velocity does not affect vertical velocity at all! Example: If you took a bullet and shot it out of a gun at a perfectly horizontal angle (0 or 180 degrees) and dropped another bullet from the same height of the gun barrel, both bullets would hit the ground at the same time.
Ignoring air resistance, the horizontal component of velocity has no connection with, and no effect on, the vertical component. Two bodies that leave the top of the building simultaneously with the same vertical velocity hit the ground at the same time, regardless of their horizontal velocities or their masses. That's the same as saying that a bullet fired horizontally from a gun and a bullet or a stone dropped from the gun's muzzle at the same instant hit the ground at the same instant. Strange but true.
Because there's no horizontal force acting on it that would change its horizontal component of velocity. (In practice, that's not completely true, since the frictional 'force' of air resistance acts in any direction. But outside of air resistance, there's nothing else acting horizontally on the projectile.)
A stone is thrown with an angle of 530 to the horizontal with an initial velocity of 20 m/s, assume g=10 m/s2. Calculate: a) The time it will stay in the air? b) How far will the stone travel before it hits the ground (the range)? c) What will be the maximum height the stone will reach?
say shell velocity = 1000 m/s , launch angle = 45 deg from horizontal , then horizontal component = cos 45 * 1000 = 0.707 *1000 = 707 m/s
No, horizontal velocity and vertical velocity are independent and have no effect on each other.
does the color of a lease affect the velocity of the light waves projected by the laser?
You cannot because you do not know how long before the object falls to the ground and so stops moving.