A tight guitar string has a frequency of 540 Hz as its third harmonic what will be its fundamental frequency if it is fingered at a length of only 60 percent of its original length?

Answer 1

normal fundamental- 180 Hz

(open- open) =

540 Hz at 3rd- f at 3rd= 3f' 540 =180

it's wavelength= v/f= 343/180= 1.9

L= 3/2 (wavelength)= 2.85

60% of this = 1.71= new wavelength

v= f x wavelength

343/ 1.71= 200 Hz

Answer 2

If the third harmonic of the string is 540 Hz, then the fundamental frequency of the string is one-third of 540 Hz, which is 180 Hz. When the string is fingered at 60% of its length, the fundamental frequency will decrease because the shorter length results in a higher pitch. To find the new fundamental frequency, you can use the formula: (f = nf_0) where (f_0) is the original fundamental frequency.