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What is the relationship between the momentum and wavelength of an electron?
The relationship between the momentum and wavelength of an electron is described by the de Broglie hypothesis, which states that the wavelength of a particle is inversely proportional to its momentum. This means that as the momentum of an electron increases, its wavelength decreases, and vice versa.
Who first wrote the electron waves equation that led to the mechanical model?
Erwin Schrodinger, a German physicist,
What is the De Broglie wavelength of an electron that strikes the back of the face of a TV screen at 19 the speed of light?
Assuming you mean that the velocity is 1/9th the speed of light then you need to use the de Broglie equation for the wavelength of a particle, which says that the wavelength is equal to Planck's constant divided by the momentum. Thus, λ = h / p = h / (m*v) = h/(m*1/9*c) = 9*h/(m*c) where λ=wavelength, h=Planck's constant, p=momentum, m=mass of the electron, v=velocity, and c=speed of light this gives λ = 9 * 6.626*10^-34 / (9.109*10^-31 * 3.00*10^8) = 2.18*10^-11 meters
When did Louis de broglie discover electron waves?
Louis de Broglie proposed the theory of electron waves in 1924 as part of his doctoral thesis, which suggested that electrons have both particle-like and wave-like properties. This marked a significant contribution to the development of quantum mechanics, laying the foundation for wave-particle duality and the concept of matter waves.
Does the de broglie wavelength of a photon become longer or shorter as its velocity increases?
The de Broglie wavelength of a photon remains constant as its velocity increases because a photon always travels at the speed of light in a vacuum. The wavelength of light is determined by its frequency according to the equation λ = c / f.
If proton and an electron have the same speed which has the longer de Broglie wavelength?
It is electron since wavelength = h/(mv), and since proton's mass > electron's mass, electron's wavelength is longer.
What is de broglie's wavelength of electron in meters travelling at half a speed of light?
4.2*10-11
What is the relationship between the momentum and wavelength of an electron?
The relationship between the momentum and wavelength of an electron is described by the de Broglie hypothesis, which states that the wavelength of a particle is inversely proportional to its momentum. This means that as the momentum of an electron increases, its wavelength decreases, and vice versa.
An electron starting from rest accelerates through a potential difference of 388 V What is the final de Broglie wavelength of the electron assuming that its final speed is much less than the spee?
To find the final de Broglie wavelength, you can use the equation λ = h/p, where λ is the wavelength, h is Planck's constant, and p is the momentum of the electron. The momentum can be calculated as p = √(2mE), where m is the mass of the electron and E is the kinetic energy acquired from the potential difference. Find the final speed of the electron using the equation v = √(2eV/m), where e is the elementary charge. Finally, use the speed to calculate the final momentum and plug it into the de Broglie wavelength formula.
Who stated that matter behaves as both waves and particles?
Louis de Broglie
Who first wrote the electron waves equation that led to the mechanical model?
Erwin Schrodinger, a German physicist,
When did Jean de Broglie die?
Jean de Broglie died in 1976.
What is the De Broglie wavelength of an electron that strikes the back of the face of a TV screen at 19 the speed of light?
Assuming you mean that the velocity is 1/9th the speed of light then you need to use the de Broglie equation for the wavelength of a particle, which says that the wavelength is equal to Planck's constant divided by the momentum. Thus, λ = h / p = h / (m*v) = h/(m*1/9*c) = 9*h/(m*c) where λ=wavelength, h=Planck's constant, p=momentum, m=mass of the electron, v=velocity, and c=speed of light this gives λ = 9 * 6.626*10^-34 / (9.109*10^-31 * 3.00*10^8) = 2.18*10^-11 meters
What is the speed of the electron with a de Broglie wavelength of 235nm?
The DeBroglie wavelength of an electron with 1 eV KE and rest mass energy 0.511 MeV is 1.23 nm. This is around a thousand times smaller than a 1 eV photon. To find the DeBroglie wavelength of an electron, simply divide Planck's constant by the momentum of the electron.
When did Louis de broglie discover electron waves?
Louis de Broglie proposed the theory of electron waves in 1924 as part of his doctoral thesis, which suggested that electrons have both particle-like and wave-like properties. This marked a significant contribution to the development of quantum mechanics, laying the foundation for wave-particle duality and the concept of matter waves.
How did de broglie test his theory?
de Broglie waves for electrons have wavelengths similar to that of x-rays, which diffract when sent through certain crystals according to the Laue phenomenon. These wavelengths where fist confirmed by diffraction by Davisson and Germer.
What is Victor de Broglie's birthday?
Victor de Broglie was born on November 28, 1785.
