X = 1/2 G t2
t = sqrt( 2X/G )
= sqrt ( 200/9.8 )
= sqrt (20.408 )
= 4.518 seconds (rounded)
When an object is dropped from a certain height, the time it takes to reach the ground is independent of the height (assuming no air resistance). Therefore, whether you drop the object from three times the initial height or the original height, it will still take the same time (T) to reach the ground.
Germs can transfer to food within seconds of being dropped on the ground. The risk of contamination depends on factors such as the cleanliness of the surface, the type of food, and how long it stays on the ground. It is generally recommended to follow the 5-second rule — if food is picked up quickly, the risk of contamination is lower.
Both weights will fall at the same rate due to gravity. The acceleration due to gravity is constant regardless of the mass of the object, so both weights will reach the ground at the same time when dropped from the same height.
The duration an object is in the air is commonly referred to as "hang time." This term is often used in sports and physics to describe how long an object remains airborne before returning to the ground.
The ball would take approximately 4 seconds to hit the ground, neglecting air resistance. This calculation is based on the constant acceleration due to gravity (9.8 m/s²), assuming the ball is dropped and not thrown.
2s
When an object is dropped from a certain height, the time it takes to reach the ground is independent of the height (assuming no air resistance). Therefore, whether you drop the object from three times the initial height or the original height, it will still take the same time (T) to reach the ground.
It depends plus, you can't go to the top of the leaning tower of Pisa.
Assuming the object is dropped from rest and neglecting air resistance, it would take approximately 7.0 seconds for the object to hit the ground from a height of 500 feet. This is based on the formula t = sqrt(2h/g), where t is the time, h is the height, and g is the acceleration due to gravity (approximately 32.2 ft/s^2).
D = 1/2 g T2T = sqrt(2D/g) = sqrt( 109.2 / 9.8 ) = 3.335 seconds(rounded)
A pebble is dropped from the top of a 144-foot building. The height of the pebble h after t seconds is given by the equation h=−16t2+144 . How long after the pebble is dropped will it hit the ground?Interpretationa) Which variable represents the height of the pebble, and in what units?b) Which variable represents the time in the air, and in what units?c) What equation relates the height of the object to its time in the air?d) What type of equation is this?e) What are you asked to determine?
The ESB is much wider at its base than at its top, so no object dropped from its top would hit the sidewalk. HOWEVER, an object dropped from the height of the ESB would, if it experienced no air friction nor hit anything along the way, would hit the ground in 8.8 seconds. However, air friction would delay this by a few seconds, as a small ball would experience air resistance before that time.
In a vacuum, just under 9 seconds. In the real world, more than that, but it depends on the shape of the object and the prevailing winds and air currents.
4 Seconds
Assuming they were in a vacuum, if both objects were dropped from th esame height, then both take the same length of time to reach the ground. All masses fall with the same acceleration, reach the same speed in the same period of time, and hit the ground at the same time. Otherwise and if there is an atmosphere or if they are dropped from different heights, you have not presented information; shape and size are the most important factors.
Germs can transfer to food within seconds of being dropped on the ground. The risk of contamination depends on factors such as the cleanliness of the surface, the type of food, and how long it stays on the ground. It is generally recommended to follow the 5-second rule — if food is picked up quickly, the risk of contamination is lower.
a pool, a building, the ocean.