0
If you can ignore the effects of air resistance, then . . .
The speed of a falling object is
S = s0 + G TS =speed at any time after it's dropped
s0 =
initial speed you gave it when you dropped it; if you just opened
your hand and let it roll out, then s0 is zero.
G =
acceleration of gravity; On Earth: 9.8 meters (32.2 feet) per second2
T =
length of time it has been falling.
That's the speed of the falling object, also the magnitude of its velocity.
The direction of velocity is on a line toward the center of the Earth, typically
referred to in most places as "down".
What else can I help you with?
Below is the rule for calculating the velocity of a falling object Use this rule to calculate the rate expressed in feet per second that a piano dropped 5 seconds ago is falling?
The rule for calculating the velocity of a falling object is V = gt, where V is the velocity, g is the acceleration due to gravity (32 ft/s^2), and t is the time in seconds. Plugging in the values: V = (32 ft/s^2) x 5 seconds = 160 ft/s. Therefore, the piano dropped 5 seconds ago is falling at a rate of 160 feet per second.
Is there a graph of the acceleration rate of a falling object?
Yes, the acceleration rate of a falling object can be graphed over time. The graph typically shows the acceleration increasing due to gravity until it reaches a constant value (9.8 m/s2) once the object reaches terminal velocity or lands on the ground.
Does the speed of an object in air continue to increase until it hits the ground?
It depends on how high it is when it start falling. If it is high enough, it will reach its terminal velocity and stop accelerating before it hits the ground. As an object is falling, it has to push through air below it. The faster it falls, the greater the air resistance (or drag) to the object. At some point, the amount of air resistance will be equal to the pull of gravity (its weight) and it will not be able to go any faster. We call this its terminal velocity, the maximum speed it can reach as it is falling through air. A larger or wider object will have more drag than a smaller object of the same weight and will have different maximum speeds. That is why a person falling from a plane with a parachute will stop going faster after the parachute opens and the drag increases because of the shape of the open parachute.
As a freely falling object speeds up what is happening to its acceleration due to gravity?
Its acceleration due to gravity is constant. The acceleration is equal to the object's change in speed every second. I've tried to illustrate the constantly-increasing falling speed in my diagram below.
What is the quantity which is measured by the area occupied below the velocity - time graph?
Distance travelled (displacement). Distance = velocity/time, so velocity * time = distance. Likewise, x = dv/dt so the integral of velocity with respect to time (area under the graph) is x, the distance travelled.
Below is the rule for calculating the velocity of a falling object Use this rule to calculate the rate expressed in feet per second that a piano dropped 4 seconds ago is falling?
128
Below is the rule for calculating the velocity of a falling object Use this rule to calculate the rate expressed in feet per second that a piano dropped 3 seconds ago is falling?
The rule for calculating the velocity of a falling object is V = gt, where V is velocity, g is the acceleration due to gravity (32 ft/s^2), and t is time. For an object dropped 3 seconds ago, the velocity would be V = 32 ft/s^2 * 3 s = 96 ft/s.
Below is the rule for calculating the velocity of a falling object Use this rule to calculate the rate expressed in feet per second that a piano dropped 5 seconds ago is falling?
The rule for calculating the velocity of a falling object is V = gt, where V is the velocity, g is the acceleration due to gravity (32 ft/s^2), and t is the time in seconds. Plugging in the values: V = (32 ft/s^2) x 5 seconds = 160 ft/s. Therefore, the piano dropped 5 seconds ago is falling at a rate of 160 feet per second.
Is there a graph of the acceleration rate of a falling object?
Yes, the acceleration rate of a falling object can be graphed over time. The graph typically shows the acceleration increasing due to gravity until it reaches a constant value (9.8 m/s2) once the object reaches terminal velocity or lands on the ground.
Can you sucsesfully shoot a falling object?
Yes but you have to aim below where the ball is at the time of firing.
Does the speed of an object in air continue to increase until it hits the ground?
It depends on how high it is when it start falling. If it is high enough, it will reach its terminal velocity and stop accelerating before it hits the ground. As an object is falling, it has to push through air below it. The faster it falls, the greater the air resistance (or drag) to the object. At some point, the amount of air resistance will be equal to the pull of gravity (its weight) and it will not be able to go any faster. We call this its terminal velocity, the maximum speed it can reach as it is falling through air. A larger or wider object will have more drag than a smaller object of the same weight and will have different maximum speeds. That is why a person falling from a plane with a parachute will stop going faster after the parachute opens and the drag increases because of the shape of the open parachute.
What does area under velocity time graph represents?
The area under a velocity-time graph represents the displacement of an object over a given time interval. This area can be calculated by finding the integral of the velocity function with respect to time. If the graph is above the time axis, the displacement is positive; if it's below, the displacement is negative. The shape of the area can vary depending on the velocity function, leading to different methods for calculating it, such as using geometric shapes or calculus.
As a freely falling object speeds up what is happening to its acceleration due to gravity?
Its acceleration due to gravity is constant. The acceleration is equal to the object's change in speed every second. I've tried to illustrate the constantly-increasing falling speed in my diagram below.
What is the quantity which is measured by the area occupied below the velocity - time graph?
Distance travelled (displacement). Distance = velocity/time, so velocity * time = distance. Likewise, x = dv/dt so the integral of velocity with respect to time (area under the graph) is x, the distance travelled.
What do you need know to find an objects velocity?
The distance it travels in a caertain amount of time as well as the direction
What is the definition of negative velocity?
Observe that the object below moves in the negativedirection with a changing velocity. An object which moves in the negative direction has a negative velocity. If the object is speeding up then its acceleration vector is directed in the same direction as its motion (in this case, a negative acceleration).
The rule below sHow is how to find the position of a falling object Which answer expresses that rule in the form of an equation?
F(t) = h - 16t2
