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Na (g)------>Na++ e-

The first ionization energy is I=495,8 kJ/mol, and for one atom the energy is:

495,8/6,02214129 = 8,235·10-19 J/atom

E=hv=hc/λ and:

λ=hc/E= (6,626 069 57·10-34 J·s)(3,00·108 m/s)/8,235.10-19 J/atom = 242 nm

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Related Questions

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