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The equation for half-life decay is

AT = A0 2 (-T/H)

so, plug in 28, 24, and 84 and you get

AT = (24) 2 (-84/28)

AT = (24) (0.125)

AT = 3

Of course, that's the formal way to do it. In this case, one could also have divided 84 by 28, giving 3, which means that 3 half-lives would be used, and that is simply 1/23 or 1/8.

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Q: Chromnium-51 has a half life of 28 days. How much of a 24.0 gram sample will remain after 84 days?
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