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Q: Density of molten copper at 1200 C?

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they get up to 1200 degrees C

Boiling is 2562 °C melting is 1084.62 °C

It is the ratio of the density of MgSO4 (@ 20 C) to the density of H2O (@ 4 C). the density of water at this T is 1000 kg/M^3 or 1 g/cm^3. So just find the density of magnesium sulfate at 20 degrees C and divide by one of these densities of water. (Make sure all the units cancel out! specific gravity is dimensionless!)

The density of ultrapure water at 50 degrees Celsius is 0,98804 g/cm3.

810 kg/m^3

Related questions

All the silicates are molten at about 1200°C and all are solid when cooled to about 600°C.

Molten lava near the surface can reach 1200 deg. C, or 2200 deg. F.

copper's melting point is 1,083°C and its boiling point is 2,595°C just for fun A coin is usually, made of copper or a copper alloy. But the question was what temperature does it burn at - I'd like to know too - when copper is molten it's surface emits a blue flame, which is presumably burning copper, this happens as soon as it melts.

Density

Depending on the type and chemistry of the rocks involved, lava temperatures could range from approximately 1200 F to 2300 F (700 C to 1300 C), of course, in some parts of the mantle, rocks gets a lot hotter.

1200 Celsius = 2192 Fahrenheit .

Water has its maximum density at 4 degree C. If you cool or heat water from 4 degree C, the density will decrease. Minimum density will be at 0 C if you are cooling it from 4 C. Minimum density will be at 100 C if you are heating it.

c. 1001 and died in c. 1200

Copper Loss at 75 C = Copper Loss at Ambient Temperature C * (310/(235+Ambient Temperature C))

1200 c

The mass of copper is 240 g.Use the following formula:q = m x c x DeltaT,where:q is energy, m is mass, c is specific heat capacity, and DeltaT is the change in temperature.DeltaT = Tfinal-TinititalKnownq = 1200 calcCu = 0.0923 cal/g.oCTinitial = 20oCTfinal = 75oCDeltaT = 75oC - 20oC = 55oCUnknownmass of copperSolutionRearrange the equation q = m x c x DeltaT to isolate m. Plug in the known values and solve.m = q/(c x DeltaT)m = 1200/(0.0923 x 55) = 240 g (rounded to two significant figures)

Assumed as a single copper busbar and not considering the length: @ 30°C = 1403 Amps. @ 35°C = 1355 Amps. @ 40°C = 1306 Amps. @ 45°C = 1255 Amps.

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