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Displaced liquid and the weight of an object are the same what would the object do?
If the weight of an object is exactly equal to the weight of displaced liquid ... meaning that the object has exactly
the same density as the liquid ... then the object has "neutral buoyancy". It behaves in the liquid as if its weight
is zero.
Wherever you put it in the liquid, it stays there, neither rising nor falling, just as a weightless astronaut does
while his ship is in orbit, or anywhere else in space with no engines firing.
What else can I help you with?
Does the weight of an object immersed in a buoyant liquid affect the buoyant force on the object?
It is not the weight of the immersed object but the volume of the object would affect the buoyant force on the immersed object because the buoyant force is nothing but the weight of the displaced liquid whose volume is equal to that of the immersed object.
What is meant by upthrust or by buoyant force?
When an object is immersed in liquid then an equal volume of liquid would be displaced to the upper surface. The weight of this expelled liquid would be used as a force to push up the immersed object. Hence it is named as upthrust or buoyant force
What are the conditions to a object to sink?
Right principle is "Archimedes Principle" When the weight of the sinking object exceeds the weight of the displaced liquid sinking continues. If otherwise the body would be pushed up and it would start floating on the surface. At the time of floating, the weight of the body = weight of the liquid displaced
How can you calculate weight of object in water if original weight of object displaced and amount of water is given?
Here's one way that would work: 1. Weigh a bowl of water. 2. Hold the object underwater with a piece of wire or straw and mark the higher water level with a grease marker. 3. Fill the bowl to the line with more water and weigh it again.
Does the amount of liquid displaced by an object depend on the object's mass?
No. It depends on the amount of space the object occupies, which is known as its "volume".Within that volume, it may have a large mass, a small mass, or an in-between mass, depending onwhat substance comprises the object. In each case, it would displace the same amount of liquid.In fact, where the question uses the slippery word "amount", it's really talking about "volume" of liquid.
What does the Archimedes principles state?
When an object is immersed in a liquid, the liquid exerts a buoyant force on the object which is equal to the weight of the liquid displaced by the object. This statement is known as Archimedes' Principle. When a solid body is immersed wholly or partially in a liquid, then there is same apparent loss in its weight. This loss in weight is equal to the weight of the liquid displaced by the body. the bouyant force of an object equal to the weight of the fluid that the object displaced .
Does the weight of an object immersed in a buoyant liquid affect the buoyant force on the object?
It is not the weight of the immersed object but the volume of the object would affect the buoyant force on the immersed object because the buoyant force is nothing but the weight of the displaced liquid whose volume is equal to that of the immersed object.
How would you verify the Archimedes principle for objects that are less dense than the liquid?
Two ways to do this: 1) Floating the less dense object on the more dense liquid. To verify the Archimedes principle you need to show that the mass of the liquid displaced by the less dense object is equal to the mass of the less dense object. To do this you need to have a way to determine the mass of the displaced liquid. If the liquid is in a container filled to the brim, then when you place the less dense object in it, the displaced liquid will spill out over the edges of the container. If you can collect and weight that liquid, then you can compare its weight to the weight of the less dense object - they should match. Alternatively, you can find a way to measure the volume of the displaced liquid and calculate the mass from the volume and density of the displaced liquid. 2) Immerse the object completely in the liquid and measure the force required to keep it submerged. This one is more complicated and difficult to execute and measure. The force required to keep the less dense object submerged should be the difference between the weight of the object (when it is not in the liquid) and the weight of the displaced liquid.
What is meant by upthrust or by buoyant force?
When an object is immersed in liquid then an equal volume of liquid would be displaced to the upper surface. The weight of this expelled liquid would be used as a force to push up the immersed object. Hence it is named as upthrust or buoyant force
How would force of buoyancy change for bodies weighing lesser?
The buoyant force is equal to the 'weight' of liquid that is displaced, which depends on the volume of liquid that is displaced, the density of the liquid, and gravitational acceleration, not the weight of the body.
What would you use to measure volume of an irregular object?
I would place it in a container full of liquid after measuring the liquid. I would measure the amount of liquid displaced by the object. That amount is equal to the volume of the irregular object if it is fully submerged in the liquid.
What are the conditions to a object to sink?
Right principle is "Archimedes Principle" When the weight of the sinking object exceeds the weight of the displaced liquid sinking continues. If otherwise the body would be pushed up and it would start floating on the surface. At the time of floating, the weight of the body = weight of the liquid displaced
What is the density of a liquid if a copper whose density is 8.93 g per cm3 weighs 180 g in air and 162 g when immersed in a liquid?
The weight of the copper in the liquid is equal to its weight in air minus the weight of the liquid displaced. Using the weight difference, we can find the volume of the liquid displaced. Then, using the volume and the weight of the liquid displaced, we can calculate the density of the liquid, which in this case would be 8.93 g/cm3.
How can you calculate weight of object in water if original weight of object displaced and amount of water is given?
Here's one way that would work: 1. Weigh a bowl of water. 2. Hold the object underwater with a piece of wire or straw and mark the higher water level with a grease marker. 3. Fill the bowl to the line with more water and weigh it again.
Does the amount of liquid displaced by an object depend on the object's mass?
No. It depends on the amount of space the object occupies, which is known as its "volume".Within that volume, it may have a large mass, a small mass, or an in-between mass, depending onwhat substance comprises the object. In each case, it would displace the same amount of liquid.In fact, where the question uses the slippery word "amount", it's really talking about "volume" of liquid.
What would you use to measure an irregular objects volume?
I would place it in a container full of liquid after measuring the liquid. I would measure the amount of liquid displaced by the object. That amount is equal to the volume of the irregular object if it is fully submerged in the liquid.
What scientific rule states that the buoyant force an an object is equal to the weight of the fluid displaced by the object?
Since the object is submerged, we know that the buoyant force is not sufficient to overcome the weight of the object, otherwise it would be floating rather than being submerged. Therefore, the buoyant force is equal to the weight of the displaced water, not the weight of the object itself.
