The buoyant force on a floating object depends on the weight of the fluid displaced by the object, not on the weight of the object itself. This is known as Archimedes' principle.
The weight of water displaced by a floating body is equal to the weight of the body itself. This is known as Archimedes' principle, which states that the buoyant force acting on a body immersed in fluid is equal to the weight of the fluid displaced by the body.
The weight of the fluid displaced by a floating body is equal to the weight of the floating body itself. This is known as Archimedes' principle. The volume of fluid displaced by a floating body is equal to the volume of the part of the body that is submerged in the fluid.
The buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid displaced by that object. This relationship is described by Archimedes' principle, which states that the buoyant force is equal to the weight of the displaced fluid regardless of the weight of the object itself.
The upward bouyant force depends only on the weight of the displaced fluid. The NET force (object's weight - bouyant force) depends on the object's weight and will determine how fast it sinks.
The mass of the water displaced by an object times the acceleration gravity (commonly denoted as "g" and known to be 9.81 m/s2 on or near the surface of the Earth) equals the buoyant force. This is shown as:Fbuoy= mgFbuoy is the buoyant force on the objectm is the mass of the water displaced by the objectg is the gravitational constantI think what you were really trying to ask is, "what is the relationship between the weight of the displaced water of an object and the buoyant force acting on the object?"In this case I would have answered that the buoyant force on an object is equal to the weight of the water displaced by the object.
The weight of water displaced by a floating body is equal to the weight of the body itself. This is known as Archimedes' principle, which states that the buoyant force acting on a body immersed in fluid is equal to the weight of the fluid displaced by the body.
The buoyant force on an object depends only on the weight of the fluid displaced: Fb = Vd*ρf*g Vd may not be the volume of the object; for example: if the object is floating on the liquid surface. Also, there may be other forces acting on the object, such as its weight (Mo*g)
The weight of the fluid displaced by a floating body is equal to the weight of the floating body itself. This is known as Archimedes' principle. The volume of fluid displaced by a floating body is equal to the volume of the part of the body that is submerged in the fluid.
The buoyant force acting on an object submerged in a fluid is equal to the weight of the fluid displaced by that object. This relationship is described by Archimedes' principle, which states that the buoyant force is equal to the weight of the displaced fluid regardless of the weight of the object itself.
Since the object is submerged, we know that the buoyant force is not sufficient to overcome the weight of the object, otherwise it would be floating rather than being submerged. Therefore, the buoyant force is equal to the weight of the displaced water, not the weight of the object itself.
The upward bouyant force depends only on the weight of the displaced fluid. The NET force (object's weight - bouyant force) depends on the object's weight and will determine how fast it sinks.
The mass of the water displaced by an object times the acceleration gravity (commonly denoted as "g" and known to be 9.81 m/s2 on or near the surface of the Earth) equals the buoyant force. This is shown as:Fbuoy= mgFbuoy is the buoyant force on the objectm is the mass of the water displaced by the objectg is the gravitational constantI think what you were really trying to ask is, "what is the relationship between the weight of the displaced water of an object and the buoyant force acting on the object?"In this case I would have answered that the buoyant force on an object is equal to the weight of the water displaced by the object.
It is not the weight of the immersed object but the volume of the object would affect the buoyant force on the immersed object because the buoyant force is nothing but the weight of the displaced liquid whose volume is equal to that of the immersed object.
The buoyant force on a submerged object depends on the volume of the object. It is equal to the weight of the fluid displaced by the object, which is determined by its volume. The weight of the object itself affects the net force experienced by the object when submerged.
It can be, or it can be less than the weight of the object.The buoyant force is equal to the weight of the displaced fluid.
The amount of fluid displaced by a submerged object depends on the volume of the object itself. This is known as Archimedes' principle, which states that the buoyant force on an object is equal to the weight of the fluid displaced by the object.
If the cork is floating, then part of it is underwater and part of it is abovewater. The part that's above water is not displacing water, so the volumedisplaced is less than the total volume of the cork.Here's a mantra that will, come in very handy if you memorize it and thenfile it away until you need it:"A sinking object displaces its volume.A floating object displaces its weight." I can't think of any way that an object in water could displace morethanits volume.