How do you calculate height by timing a falling object'?

Answer 1

There is a simple equasion that gives an approximate answer. h = 1/2 g t2 This is not completely accurate, as it ignores the effects of air resistance of an object, but ofers a very close approximate for most common objects. ( a feather will not fall as fast as a ball due to air resistance. This calculation assumes a vaccume to be completely accurate. ) The value g is gravity. In Metric this is 9.81 m/s/s usually calculated as 9.8 or simply as 10 if you are doing the calculation s in your head. The value t is the time taken. The result h is the distance or the height in meters. If someone jumps off a bridge into the water below, and he takes 2.5 seconds from the bridge to the water we can calculate the height of the bridge. height = 1/2 ( 9.81 x (2.52)) height = 1/2 ( 9.81 x 6.25) height = 1/2 61.3125 height = 30.6562 meters

Answer 2

It is pretty easy,

By the third equation of motion,

s = ut + 1/2at2

where,

u is initial velocity,

t is time of fall,

a is acceleration.

u= zero as we are not giving any velocity in downward direction(mean we only drop it & not throw in downwards).

a = acceleration due to gravity(g = 9.81 m/s2).

s = height to be calculated.

t = time taken to fall.

(putting the values) s = 0 * t + 1/2 * 9.81 * t2

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| s = 4.905 * t2 |

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Note : Be careful of units. s will come in meters(m) only if time is taken in seconds(s).

Answer 3

You can calculate the height of a falling object by using the formula: h = 0.5 * g * t^2, where h is the height, g is the acceleration due to gravity (approximately 9.81 m/s^2), and t is the time the object takes to fall. Simply measure the time it takes for the object to fall and plug that value into the formula to calculate the height.