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How do you calculate the speed of something dropped from 30 feet in the air?
Wiki User
∙ 15y ago
You have to use the equations of motion; these were derived from Newton's laws of motions.
There are four equations that, essentially, allow you to calculate velocity, position, acceleration and time for bodies in motion.
As you are after the speed, we use the equation that calculates velocity (velocity is equivalent to speed plus direction, and for this problem, we can ignore the direction). The equation is:
v2 = u2 + 2as
Where v is the final velocity, u is the initial velocity, a is the accelaration and s is the distance.
we know three of these values:
u = 0 (the object is initially stationary)
a = 32 (the accelaration due to gravity is 32 feet per second per second)
s = 30 (the distance dropped)
Plugging these values into the equation gives:
v2 = 2 x 32 x 30
or
v2 = 1920
v = sqr(1920)
v = 43.8 feet per second (approx. 29 mph).
This does ignore the effects of wind resistance - for example, if you drop a feather, then the wind resistance will greatly slow its fall).
Wiki User
∙ 15y ago
The speed of an object dropped from a certain height can be calculated using the equation v = √(2gh), where v is the speed, g is the acceleration due to gravity (approximately 9.8 m/s^2), and h is the height. In order to calculate the speed in feet per second, you would need to convert the height of 30 feet to meters (i.e., 30 * 0.3048).
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