0
You have to use the equations of motion; these were derived from Newton's laws of motions.
There are four equations that, essentially, allow you to calculate velocity, position, acceleration and time for bodies in motion.
As you are after the speed, we use the equation that calculates velocity (velocity is equivalent to speed plus direction, and for this problem, we can ignore the direction). The equation is:
v2 = u2 + 2as
Where v is the final velocity, u is the initial velocity, a is the accelaration and s is the distance.
we know three of these values:
u = 0 (the object is initially stationary)
a = 32 (the accelaration due to gravity is 32 feet per second per second)
s = 30 (the distance dropped)
Plugging these values into the equation gives:
v2 = 2 x 32 x 30
or
v2 = 1920
v = sqr(1920)
v = 43.8 feet per second (approx. 29 mph).
This does ignore the effects of wind resistance - for example, if you drop a feather, then the wind resistance will greatly slow its fall).
What else can I help you with?
Is the speed uniform or nonuniform of a stone dropped from a height?
The speed of a dropped stone will be non-uniform. The stone goes faster as it falls by an amount equal to 32 feet per second, per second. That means for each second of falling, the speed increases by another 32 feet per second until terminal velocity is reached.
An object is dropped from a platform of 100 feet high ignoring wind resistance what will its speed be when it reaches the ground?
The final speed of an object dropped from a height of 100 feet can be found using the equation v = sqrt(2gh), where v is the final speed, g is the acceleration due to gravity (32 ft/s^2), and h is the height (100 ft). Plugging the values into the equation gives v ≈ 80 ft/s.
Where will a coin land if you drop it in a bus moving at constant speed and in a straight line?
The coin will land straight back down in the same spot from where it was dropped in the bus, assuming the bus is moving at a constant speed in a straight line without any sudden changes in acceleration. This is because the coin is moving with the bus at the same velocity when dropped.
What is the velocity of a 4.5 Pound object falling thirty feet?
Ignoring air resistance ... Any object dropped near the Earth's surface reaches a speed of 43.9 feet per second after falling 30 feet. The velocity is 43.9 feet per second down. The object's weight makes no difference.
A ball is dropped from 10 feet above the ground.It hits the ground and bounces up half as high as it fellThis is true for each successive bounce.What height does the ball reach on the fourth bounce?
After each bounce, the ball reaches half of the height from which it was dropped. Since the ball was initially dropped from 10 feet, on the first bounce it will reach 5 feet, on the second bounce it will reach 2.5 feet, on the third bounce it will reach 1.25 feet, and on the fourth bounce it will reach 0.625 feet.
What is the speed of a quarter if dropped from 6 feet?
The fact that it is a quarter is totally irrelevant. It will hit the ground at a speed of 19.6 feet/sec.
How far was the atomic bomb dropped?
The two bombs dropped on Japan were released at a little higher than 30,000 feet and exploded at about 1500 feet. You can calculate from there. Bombs dropped for test purposes have been released and exploded at different altitudes.
How do measure the square feet of something that is not square?
Calculate the area.
What is the speed of an object weighing 80 pounds dropped from 7 feet?
it strikes the ground at a velocity of 17.9 ft/s
When a body is dropped how is the velocity related to time?
When a body is dropped . . . -- The speed keeps increasing. -- The speed is always 32.2 feet per second (9.8 meters per second) faster than it was one second earlier. -- The direction of the speed is always downward, and never changes. -- Combining the speed and direction gives you the velocity.
How fast is a pound moving if dropped 30 feet?
To determine the speed of a pound (or any object) dropped from a height of 30 feet just before it hits the ground, we can use the equation derived from the laws of physics: ( v = \sqrt{2gh} ), where ( g ) is the acceleration due to gravity (approximately 32.2 feet per second squared) and ( h ) is the height (30 feet). Plugging in the values, the speed would be approximately ( v = \sqrt{2 \times 32.2 \times 30} ), which yields a final speed of about 24.3 feet per second just before impact.
Is the speed uniform or nonuniform of a stone dropped from a height?
The speed of a dropped stone will be non-uniform. The stone goes faster as it falls by an amount equal to 32 feet per second, per second. That means for each second of falling, the speed increases by another 32 feet per second until terminal velocity is reached.
How fast is 200 feet In 6 seconds?
22.73 mph
A man standing on solid concrete dropped a tomato 6 feet but it did not break why?
he dropped it from 7 feet in the air. (:
How many feet in an hour?
The number of feet in an hour depends on the speed of movement. For example, if someone walks at a pace of 3 miles per hour, they would cover 15,840 feet in an hour (since 1 mile equals 5,280 feet). If you have a specific speed in mind, you can calculate the feet traveled by multiplying the speed in miles per hour by 5,280.
An object is dropped from a platform of 100 feet high ignoring wind resistance what will its speed be when it reaches the ground?
The final speed of an object dropped from a height of 100 feet can be found using the equation v = sqrt(2gh), where v is the final speed, g is the acceleration due to gravity (32 ft/s^2), and h is the height (100 ft). Plugging the values into the equation gives v ≈ 80 ft/s.
How much is 400 feet in 52.4 seconds?
To find the speed in feet per second, divide the distance by the time: 400 feet ÷ 52.4 seconds = approximately 7.64 feet per second. This means that if something travels 400 feet in 52.4 seconds, it moves at that speed.
