Halve the frequency of the wave.
To double the frequency of a wave, you need to halve either the wavelength or the wave velocity. This is because frequency is inversely proportional to both wavelength and wave velocity. So, if you decrease either the wavelength or the wave velocity by half, the frequency will double.
If the frequency of a wave is halved, the wavelength would double. This is because the speed of the wave remains constant, so by halving the frequency (which is the number of wave cycles per unit time), each wave cycle now covers a longer distance, resulting in a longer wavelength.
You actually answered your own question. The wavelength remains the same since it is stated as part of the problem. However, the frequency, which I am betting you are more interested in will double. The frequency is releated to the wavelength and the speed of the wave by the following equation f = v/l where f is the frequency, v is the speed, and l is the wavelength. So if the velocity doubles and the wavelength is constant, then the frequency will double.
The product of (frequency) times (wavelength) is always the same number. (It happens to be the speed of the wave.) So if one of them doubles, the other one gets decreased by half.
A radio wave has a greater wavelength compared to a visible light wave.
To double the frequency of a wave, you need to halve either the wavelength or the wave velocity. This is because frequency is inversely proportional to both wavelength and wave velocity. So, if you decrease either the wavelength or the wave velocity by half, the frequency will double.
Wavelength = 1/frequency. If you double the frequency, the wavelength drops to half.
If the frequency of a wave is halved, the wavelength would double. This is because the speed of the wave remains constant, so by halving the frequency (which is the number of wave cycles per unit time), each wave cycle now covers a longer distance, resulting in a longer wavelength.
Speed = wavelength x frequency, so wavelength = speed / frequency. Therefore, the wavelength is inversely proportional to the frequency. Double the frequency means half the wavelength.
You actually answered your own question. The wavelength remains the same since it is stated as part of the problem. However, the frequency, which I am betting you are more interested in will double. The frequency is releated to the wavelength and the speed of the wave by the following equation f = v/l where f is the frequency, v is the speed, and l is the wavelength. So if the velocity doubles and the wavelength is constant, then the frequency will double.
If the frequency becomes double what it was, then the wavelength becomes 1/2 of what it was.
The product of (frequency) times (wavelength) is always the same number. (It happens to be the speed of the wave.) So if one of them doubles, the other one gets decreased by half.
The distance between successive identical parts of a wave is called the wave length.
Wavelength*Frequency = Velocity of the wave. or Wavelength/Period = Velocity of the wave.
A radio wave has a greater wavelength compared to a visible light wave.
The distance between a wavelength and a wave is dependent on the speed of the wave and the frequency of the wave. This relationship is described by the equation: wavelength = speed of the wave / frequency.
you find out a waves speed by taking the wavelength and divide it by it's wave period or how long it takes for the wave to complete a full wavelength. This is what my textbook said. Speed=Wavelength ×Frequency