You can either halve the wavelength, keeping the wave speed constant; or double the wave speed, keeping the wavelength constant.
You actually answered your own question. The wavelength remains the same since it is stated as part of the problem. However, the frequency, which I am betting you are more interested in will double. The frequency is releated to the wavelength and the speed of the wave by the following equation f = v/l where f is the frequency, v is the speed, and l is the wavelength. So if the velocity doubles and the wavelength is constant, then the frequency will double.
Assuming that the wavelength remains constant, the velocity of the rope will also double if the frequency is doubled. This can be seen in the word equation below: speed = frequency x wavelength If we assume that wavelength is a constant...let wavelength = 1 speed = frequency therefore... 2 x frequency = 2 x speed
The wavelength would double.
Halve the frequency of the wave.
The product of (frequency) times (wavelength) is always the same number. (It happens to be the speed of the wave.) So if one of them doubles, the other one gets decreased by half.
You actually answered your own question. The wavelength remains the same since it is stated as part of the problem. However, the frequency, which I am betting you are more interested in will double. The frequency is releated to the wavelength and the speed of the wave by the following equation f = v/l where f is the frequency, v is the speed, and l is the wavelength. So if the velocity doubles and the wavelength is constant, then the frequency will double.
Assuming that the wavelength remains constant, the velocity of the rope will also double if the frequency is doubled. This can be seen in the word equation below: speed = frequency x wavelength If we assume that wavelength is a constant...let wavelength = 1 speed = frequency therefore... 2 x frequency = 2 x speed
Wavelength = 1/frequency. If you double the frequency, the wavelength drops to half.
wavelength
The wavelength would double.
Speed = wavelength x frequency, so wavelength = speed / frequency. Therefore, the wavelength is inversely proportional to the frequency. Double the frequency means half the wavelength.
Halve the frequency of the wave.
If the frequency becomes double what it was, then the wavelength becomes 1/2 of what it was.
The product of (frequency) times (wavelength) is always the same number. (It happens to be the speed of the wave.) So if one of them doubles, the other one gets decreased by half.
The wavelength of a wave would double if the frequency was cut in half. Wavelength=c/frequency where c equals the speed of light.
In a vacuum, all electromagnetic waves have the same propagation speed of c = 300,000,000 meters per second (the speed of light). All of these waves, however, may have different frequencies and thus wavelengths. The speed of a wave is related to its frequency and wavelength by the relation (speed) = (frequency) X (wavelength) Since the speed of electromagnetic waves in a vacuum is constant, the frequency and wavelength are "inversely proportional" to one another. This means that cutting the frequency of a wave in half makes its wavelength double, and vice versa.
Using the wave equation: Speed = frequency * wavelength, v = fλ v = speed in meters/second (m/s) f = frequency in Hertz (Hz) λ = wavelength in meters (m) and plugging in the given values, I got v =16.359 m/s, but double check me.