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I assume you are asking this in regards to an inclined plane so I will answer it accordingly,
Well Recall the equation
Force = Mass x Acceleration.
In the case of free falling objects Acceleration is equal to gravity, however, on an inclined plan the presence of an incline prevents the object from falling straight down. Instead it must accelerate with some component of gravity.
Now recall that perpendicular forces of action on an Incline plane are calculated by Sin theta and that perpendicular forces ( the normal force) is calculated by Cos theta
Hence because the object is accelerating down an incline the formula for its total force parallel to the object would be
Force = mg sin theta
Now if you remember, if you simply remove the mass from the above equation you will be left with the acceleration component of the problem ala the force = mass x acceleration formula.
So gsintheta represents A ( acceleration) in the Force = mass times acceleration formula.
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Does the angle of incline depend on the acceleration of gravity?
The only force acting on the object (let's say a cart) that is released at a certain inclination (30 degrees) is gravity. If we follow the formulas: Fgx=mgSinO Fnet=ma Fgx=Fnet Therefore: mgSinO=ma and you can simplify this formula to: gSinO=a m= mass g= gravitational force (9.8m/s^2) SinO= sin of angle (Sin30 degrees) a=acceleration
The acceleration of a bullt is measured in g's what is g?
acceleration due to gravity
Find the Lagrangian of simple pendulum?
The generalized coordinate for the pendulum is the angle of the arm off vertical, theta. Theta is 0 when the pendulum arm is down and pi when the arm is up. M = mass of pendulum L = length of pendulum arm g = acceleration of gravity \theta = angle of pendulum arm off vertical \dot{\theta} = time derivative of \theta What are the kinetic and potential energies? Kinetic energy: T = (1/2)*M*(L*\dot{\theta})^2 Potential energy: V' = MLg(1-cos(\theta)) V = -MLg*cos(\theta) --note: we can shift the potential by any constant, so lets choose to drop the MLg The Lagrangian is L=T-V: L = (1/2)ML^2\dot{\theta}^2 + MLg*cos(\theta)
Can acceleration be measured in g?
Yes. The number of 'G' in an acceleration is the acceleration in [ meters per second2 ] divided by 9.8Or the acceleration in [ feet per second2 ] divided by 32.2
A boy kicks a football with an initial velocity of 28.0 ms at an angle of 60.0 above the horizontal What is the highest elevation reached by the football in its trajectory?
Use the equation Vy=Voy-gt Because we are talking about the highest point we know that Vy=0 (i.e. the football is no longer moving up). Therefore set the equation equal to zero 0=Voy-gt Voy=gt Next, use the equation Voy=sin(theta) Replace Voy with "gt" because Voy=gt in this case (see above) You get: gt=sin(theta) You know theta = 20 degrees and t=2seconds G is a constant that = 9.81m/s^2 Plug in the numbers Christie
Use of an inclined plane in physics Hey guys I'm doing a prac investigation on an inlcined plane. I was wondering does mass affect acceleration down the incline?
inclined planes can be used in the investigation of acceleration. specificaly using m*g*sin(theta)=a (well i think that was the equation) acceleration is equal to mass*gravity*sin(theta) where sin(theta) is equal to opposite(o) over hypotenuse(h) or theta = (1/sin) * o/h
Why does the acceleration of an object rolled down an incline increase as the angle of incline increases?
The contribution of the acceleration of gravity in the direction of motion increases as the angle of the incline increases. Or in other words, as the angle between the direction of motion and the force of gravity goes to zero, the acceleration of the object goes to the gravitational acceleration. a = g cos(theta) Where theta is the angle between the direction of motion and verticle, which is in fact (theta = 90 - angle of the incline)Where a is the acceleration of the object down the incline plane and g is the acceleration due to gravity. Theta is the angle between the direction of motion of the accelerating object and the acceleration of gravity. Initially, the angle between a and g is 90 degrees (no incline) and therefore g contributes nothing to the objects acceleration. a = g cos(90) = 0 As the angle of the inclined is increased, the angle between a and g approaches zero, at which point a = g. With no other forces acting upon the object, g is its maximum acceleration.
What is the speed and acceleration of a ball rolling down a hill?
The acceleration of a tennis ball rolling down an incline depends with two factors. The force that is applied to the tennis ball and the mass of the tennis ball will determine its acceleration.
It is observed that all bodies sliding down a frictionless inclined plane have the same acceleration how does its happen?
Fx=G*sin(t) = m*g*sin(t) a=Fx/m=g*sin(t) ->> does not depend on mass
What will be the range if theta45 degrees and height is given in projectile motion?
it will only be four times the height.simply use kinematics to find the relationship between height,initial speed and angle of projection theta, ull get( u^2 sin^2theta)/2g, g of course being the acceleration due to gravity, wheras range will turn out to be (u^2 sin2(theta))/g..thump in the values..very easy to see that range is 4 times the height..cheers
Does the angle of incline depend on the acceleration of gravity?
The only force acting on the object (let's say a cart) that is released at a certain inclination (30 degrees) is gravity. If we follow the formulas: Fgx=mgSinO Fnet=ma Fgx=Fnet Therefore: mgSinO=ma and you can simplify this formula to: gSinO=a m= mass g= gravitational force (9.8m/s^2) SinO= sin of angle (Sin30 degrees) a=acceleration
In SI units what is g equal to?
If by g you mean the acceleration due to gravity,g= -9.8m/s2.g could also mean grams.
The acceleration of a bullt is measured in g's what is g?
acceleration due to gravity
Find the Lagrangian of simple pendulum?
The generalized coordinate for the pendulum is the angle of the arm off vertical, theta. Theta is 0 when the pendulum arm is down and pi when the arm is up. M = mass of pendulum L = length of pendulum arm g = acceleration of gravity \theta = angle of pendulum arm off vertical \dot{\theta} = time derivative of \theta What are the kinetic and potential energies? Kinetic energy: T = (1/2)*M*(L*\dot{\theta})^2 Potential energy: V' = MLg(1-cos(\theta)) V = -MLg*cos(\theta) --note: we can shift the potential by any constant, so lets choose to drop the MLg The Lagrangian is L=T-V: L = (1/2)ML^2\dot{\theta}^2 + MLg*cos(\theta)
Can acceleration be measured in g?
Yes. The number of 'G' in an acceleration is the acceleration in [ meters per second2 ] divided by 9.8Or the acceleration in [ feet per second2 ] divided by 32.2
A boy kicks a football with an initial velocity of 28.0 ms at an angle of 60.0 above the horizontal What is the highest elevation reached by the football in its trajectory?
Use the equation Vy=Voy-gt Because we are talking about the highest point we know that Vy=0 (i.e. the football is no longer moving up). Therefore set the equation equal to zero 0=Voy-gt Voy=gt Next, use the equation Voy=sin(theta) Replace Voy with "gt" because Voy=gt in this case (see above) You get: gt=sin(theta) You know theta = 20 degrees and t=2seconds G is a constant that = 9.81m/s^2 Plug in the numbers Christie
What is the amount of potential energy possessed by an elevated object is equal to?
The potential energy is EP= mgh where g is the gravitaional acceleration and h the elevation.
