Here WORK DONE (W)=FS COS(angle between F&S)
Supposing displacement S is in the direction of force F on the body.SO ANGLE IS ZERO. where Cos(0)=1
W= 62*S
S=W/62
=2920/62
=47.09m
This is maximum displacement she can produce in the the body of mass 20kg where as maximum work done that she can do is 2920J.
Mass of baby is not needed. Force is given as 62 N and work to be performed is 2920 J
So distance = W/F = 2920/62 = 47.1 m
30
its really easy
Sorry it is impossible to understand your question.
Horizontal force in one component of the magnetic force on earth. Horizontal is a direction, and force is any external efforts that causes an object to change.
If the horizontal velocity is constant, then the horizontal acceleration is zero,and the net horizontal force is zero.But if you are saying that the body was in constant motion and after that the force was applied, then the body will acccelerate because of the force. The net force applied on the body would be equal to the force applied to it when the body was in constant motion as here the force is in direction of the motion and hence the angle will be 0 giving the value of cos 0º as 1. Hence there would be no reduction in the net force
Angel of repose is different from the angel of friction; however in a particular case it may be the same. Basically angle of repose is an engineering property of granular materials. It is the maximum angle of a stable slope determined by friction, cohesion and the shapes of the particles. When bulk granular materials are poured onto a horizontal surface, a conical pile will form. The internal angle between the surface of the pile and the horizontal surface is known as the angle of repose and is related to the density, surface area and shapes of the particles, and the coefficient of friction of the material. Material with a low angle of repose forms flatter piles than material with a high angle of repose. In other words, the angle of repose is the angle a pile forms with the ground. While angel of friction is the angle between the noemal force and athe resultant between tha normal force and friction force.
The applied force will depend on the required force, and the angle to the ramp (or the horizontal) at which the force is applied.
Horizontal component = 14 cos(38) = 11.032 lbs (rounded)Vertical component = 14 sin(38) = 8.619 lbs (rounded)
300 beacuse 10x30=300
its really easy
Sorry it is impossible to understand your question.
The coefficient of friction is the tangent of the angle theta where the angle is measured from horizontal when the mass first starts to slip
The vertical component of the force is Fsin45 = 92 x 1/(2^1/2) = 65.2 The horizontal component of the force is FCos45 = 92 x 1/(2^1/2) = 65.2
when adhesive force becomes equal to cohesive force then the contact angle becomes 90 degree. At such a peculiar situation the meniscus remains parallel to horizontal line.
A rope exerts a force of magnitude 21 N, at an angle 31 deg above the horizontal, on a box at rest on a horizontal floor. The coefficients of friction between the box and floor are Us = 0.55 and UK = 0.50. The box remains at rest. Determine the smallest possible mass of the box. this is the full question thanks for any help! :)
Horizontal force in one component of the magnetic force on earth. Horizontal is a direction, and force is any external efforts that causes an object to change.
That is difficult to answer in that a horizontal force may be perpendicular to the body. So, the question does not differentiate between "can a vertical force cancel a horizontal force?" and "can a horizontal force cancel a horizontal force?" The best answer is, yes: two opposite and equal horizontal forces, both perpendicular to a body, will cancel each other.
The [horizontal] range of a projectile is maximised when it shoots at a 45 degree angle. This is true if air resistance is ignored so that the only force acting on the projectile is gravity.