How far will a rock drop into a well in 12 seconds?

Answer 1

First you would write down the information you know v=0m/s (final speed). Assume the rock hits the bottom of the well a= -9.8m/s (acceleration to 1 decimal place). It is always -9.8m/s for everything falling down the way t=12s s=? (displacement). This is what you are trying to figure out. Then use the equation u=v-at u=0-(-9.8x12) u=117.6m/s s=ut+1/2at2 s=(117.6x12)+(-9.8x0.5x122) s=1411.2-705.6 s=705.6 metres

Answer 2

The distance a rock will drop into a well can be calculated using the formula: distance = (1/2) * acceleration due to gravity * time^2. Assuming the acceleration due to gravity is approximately 9.81 m/s^2, the rock will have fallen approximately 708.48 meters in 12 seconds.

Answer 3

To determine how far a rock will drop into a well in 12 seconds, we can use the formula: distance = 0.5 * acceleration due to gravity * time^2. Given that the acceleration due to gravity is approximately 9.81 m/s^2, we can calculate the distance the rock will drop by substituting the values into the formula. The calculation would be: distance = 0.5 * 9.81 * (12)^2 = 0.5 * 9.81 * 144 = 705.6 meters. Therefore, the rock will drop approximately 705.6 meters into the well in 12 seconds.