Assuming (1) the object starts from rest, (2) air resistance is insignificant, the object speeds up by about 9.8 meters/second every second. That's the strength of the gravitational field. Just multiply this acceleration (9.8 meters/second2) by the time.
The speed of the object after falling for 3 seconds in free fall is 29.4 m/s.
The speed of the object after falling for 3 seconds in free fall is 29.4 m/s. This is because the acceleration due to gravity is about 9.8 m/s^2, so after 3 seconds the object would have reached a speed of 29.4 m/s.
Terminal velocity is typically reached within 10-12 seconds when falling from a height, depending on factors such as air resistance and the height of the fall.
The speed of the rock after falling for 5 seconds would be approximately 49 m/s, neglecting air resistance. This speed is the result of the acceleration due to gravity, which is approximately 9.81 m/s^2.
That depends on how long it's been falling altogether. If it was just dropped at the beginning of the 2.56 seconds, and it's only been falling for 2.56 seconds altogether, then it has fallen 32.1 meters (105.3 feet). (rounded) If it was falling for some time before the 2.56 seconds began, then it fell farther. A falling object keeps falling faster and faster as time goes on.
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The speed of the object after falling for 3 seconds in free fall is 29.4 m/s.
At the end of 3 seconds, a falling object is falling at 65.8 mph faster than when it was released, ignoring air resistance.
The speed of the object after falling for 3 seconds in free fall is 29.4 m/s. This is because the acceleration due to gravity is about 9.8 m/s^2, so after 3 seconds the object would have reached a speed of 29.4 m/s.
Ignoring air resistance, that would be about 145 feet.
Ignoring air resistance, it would be 706 meters .
If you're talking about an object falling straight downward, that object being affected by a gravitational pull of 9.81m/sec, ignoring air resistance, it would take the object around 5 seconds to reach 49m/sec.
Ignoring air resistance, it would have taken 7.3 seconds, approx.
Terminal velocity is typically reached within 10-12 seconds when falling from a height, depending on factors such as air resistance and the height of the fall.
Perhaps you meant speed or velocity, because the vertical acceleration is constant throughout the bomb's decent, ignoring the effects of air resistance. The acceleration due to gravity is 9.8 m/s2 for all values of t.
Ignoring air resistance, the velocity of any object that goes off a cliff is 29.4 meters (96.5 feet) per second downward, after 3 seconds in free-fall.
The speed of the rock after falling for 5 seconds would be approximately 49 m/s, neglecting air resistance. This speed is the result of the acceleration due to gravity, which is approximately 9.81 m/s^2.