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How fast must an object be thrown up if it is to stay in the air for 5 seconds before hitting the ground again?
An object can be thrown vertically upwards or at an angle to the ground, in both cases it is needed that time of flight be 5 seconds. This means it's time of ascent (going up) is 2.5 seconds and time of descent(coming down) is also 2.5 seconds. So, it reaches highest point 2.5 seconds after it is thrown. At highest point the vertical component of velocity1 of the object becomes zero for an instance.
Now, kinematics equation can be used to solve this.
v = uy - g*t
where v is final velocity at top =0. uy is initial vertical velocity1. g is accleration due to gravity(9.8ms-2). t is time of ascent.
putting values we get.
0 = uy - 9.8 * 2.5
or uy = 24.5 ms-1
So we need to throw an object with vertical velocity = 24.5 meters per second so that it remains in air for 5 seconds.
1. If object is thrown at an angle then vertical component of velocity of projection is taken.
If object is thrown vertically upwards then vertical component of velocity of projection is
same as velocity.
vertical component of velocity of projection(uy) = u*sin(θ), where u is velocity of projection
and θ is angle of projection with respect to horizontal.
2. Accleration due to gravity is different for different places. 9.8ms-2 is an approximate
value.
3. Here, air resistance and wind speeds have been neglected as they make the calculation very
tedious and they are always varying from time to time and place to place.
What else can I help you with?
What is the relationship between the horizontal speed of an object and its trajectory?
The horizontal speed of an object affects its trajectory by determining how far it will travel horizontally before hitting the ground. A higher horizontal speed will result in a longer horizontal distance traveled before hitting the ground, while a lower horizontal speed will result in a shorter distance.
When an object is dropped to the ground from a height of h meterswhere t is measured in seconds if an object falls 176.4 meters before it hits the ground find the time it took for the object to fall?
I have to make two assumptions:-- The object was not thrown down. Its speed was zerojust as it left the dropper's hand.-- There is no air in this question.With those assumptions . . .H = 1/2 G T2T = sqrt( 2H/G )T = sqrt( 2 x 176.4/9.8 ) = 6 seconds
A 20 kg objects falls from a height of 30 meters.How many joules of kinetic energy will the object have just before it hits the ground?
The kinetic energy just before hitting the ground can be calculated using the formula KE = 0.5 * mass * velocity^2. Since the object is falling due to gravity, the velocity just before hitting the ground can be calculated using the formula v = √(2 * g * h), where g is the acceleration due to gravity (9.8 m/s^2) and h is the height (30 m). After calculating the velocity, you can use the kinetic energy formula to find the answer.
What happens when you increase the horizontal velocity to the maximum in a projectile motion?
Increasing the horizontal velocity to the maximum in a projectile motion will cause the object to travel further horizontally before hitting the ground. This is because the horizontal velocity determines how far the object will travel in the horizontal direction before gravity pulls it down. The vertical motion of the object will remain the same, but the increased horizontal velocity will result in a longer horizontal distance traveled.
What is the displacement of the object from 2 seconds to 6 seconds?
To find the displacement from 2 seconds to 6 seconds, you need to calculate the change in position of the object during that time interval. This can be done by subtracting the position of the object at 2 seconds from its position at 6 seconds. The result will give you the displacement of the object during that time period.
What is the relationship between the horizontal speed of an object and its trajectory?
The horizontal speed of an object affects its trajectory by determining how far it will travel horizontally before hitting the ground. A higher horizontal speed will result in a longer horizontal distance traveled before hitting the ground, while a lower horizontal speed will result in a shorter distance.
When an object is dropped to the ground from a height of h meterswhere t is measured in seconds if an object falls 176.4 meters before it hits the ground find the time it took for the object to fall?
I have to make two assumptions:-- The object was not thrown down. Its speed was zerojust as it left the dropper's hand.-- There is no air in this question.With those assumptions . . .H = 1/2 G T2T = sqrt( 2H/G )T = sqrt( 2 x 176.4/9.8 ) = 6 seconds
Where is the sun's relationship to a shadow?
When a light (the sun) shines on you or any object, the object is in the way of the sunshine hitting the ground on the opposite side of the object, creating shade, or a shadow.
What determines the shadow of a groundhog or any object on the ground?
The shadow of a groundhog or any object on the ground is determined by the position of the object in relation to a light source, such as the sun. The angle and intensity of the light hitting the object affects the size and shape of the shadow it casts.
A hole in the groud caused by a meteor hitting a planet?
A solid object hitting the ground with the force of a meteor would leave a crater, a depression in the ground with a raised edge at the surface, similar to Meteor Crater in Arizona.
The distance that a free falling object falls is directly proportional to the square of the time it falls (before it hits the ground). If an object fell 91 ft in 2 seconds how far will it have fallen?
The answer is 91 ft, of course!
A 20 kg objects falls from a height of 30 meters.How many joules of kinetic energy will the object have just before it hits the ground?
The kinetic energy just before hitting the ground can be calculated using the formula KE = 0.5 * mass * velocity^2. Since the object is falling due to gravity, the velocity just before hitting the ground can be calculated using the formula v = √(2 * g * h), where g is the acceleration due to gravity (9.8 m/s^2) and h is the height (30 m). After calculating the velocity, you can use the kinetic energy formula to find the answer.
What would be the change for a 10 gram object dropped from a 20 meter building if it takes 2 seconds to reach the ground?
There is no reason for the object to change.
What happens when you increase the horizontal velocity to the maximum in a projectile motion?
Increasing the horizontal velocity to the maximum in a projectile motion will cause the object to travel further horizontally before hitting the ground. This is because the horizontal velocity determines how far the object will travel in the horizontal direction before gravity pulls it down. The vertical motion of the object will remain the same, but the increased horizontal velocity will result in a longer horizontal distance traveled.
In physics is there a negative time?
Absolutely! If an object has been already traveling for 30 seconds. If you start your watch at 30 seconds, then t = 0 at 30 seconds! The velocity of the object 3 seconds BEFORE you start the watch would then be t = -3 and 3 seconds after you start the watch would be t = 3.
In wrestling is the hitting and and kicking and object hitting real?
Some of it is real, not all of it.
What is the position of the ball at 7.5 seconds?
What is the position of the ball at 7.5 seconds
