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NUMBER OF SCREWS IN A BOX*

Size 1lb box 5 lb box 25 lb box

#7 x 1-1/4"

228

1,138

N/A

#7 x 1-5/8"

142

710

N/A

#8 x 2"

99

495

N/A

#8 x 2-1/2"

84

420

2100

#8 x3"

69

345

1725

#9 x 3-1/2"

57

280

N/A

*Screws are sold by weight not by count. Quantities listed are approximate.

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Average weight of 100 screws in box 'A' is 10.4gms it is mixed withed with150 screws of box 'B' average weight of mixed screws is 10.9 gms find the average weight of screws of box 'B'?

Let 'x' be the total weight of 100 screws in box 'A' therefore, average weight of 100 screws in box 'A' = (x / 100) = 10.4 => x = 100*10.4 = 1040 gms ............ (1) Let 'y' be the total weight of 150 screws in box 'B', therefore, average weight of 150 screws in box 'B' = (y / 150) .......... (2) After mixing 100 screws of 'A' and 150 screws of 'B', average weight of 250 screws = (x+y)/250 = 10.9 => x+y = 250*10.9 = 2725 => 1040+y = 2725 => y = 2725 - 1040 = 1685 => total weight of 150 screws of box 'B', y = 1685 gms Substitute y = 1685 in eqn (2), => average weight of screws of box 'B' = 1685/150 = 11.23 gms (approx) Hence, average weight of screws of box 'B' = 11.23 gms SHORT ANSWER """"""""""""""""" Given data: No. of screws in box 'A', NA = 100 No. of screws in box 'B', NB = 150 Average weight of 100 screws in box 'A', XA = 10.4 gms Average weight of mixed screws, XAB = 10.9 gms Average weight of 150 screws in box 'B', XB = ? Therefore, XAB = (NA XA + NB XB) / (NA + NB) 10.9 = (100*10.4 + 150XB) / (100+150) 10.9 = (1040 + 150XB) / 250 10.9*250 = 1040 + 150XB 2725 = 1040 + 150XB 2725 - 1040 = 150XB 1685 = 150XB XB = 1685/150 = 11.23 gms XB = 11.23 gms - Ratnakar Sharma


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Average weight of 100 screws in box 'A' is 10.4gms it is mixed withed with150 screws of box 'B' average weight of mixed screws is 10.9 gms find the average weight of screws of box 'B'?

Let 'x' be the total weight of 100 screws in box 'A' therefore, average weight of 100 screws in box 'A' = (x / 100) = 10.4 => x = 100*10.4 = 1040 gms ............ (1) Let 'y' be the total weight of 150 screws in box 'B', therefore, average weight of 150 screws in box 'B' = (y / 150) .......... (2) After mixing 100 screws of 'A' and 150 screws of 'B', average weight of 250 screws = (x+y)/250 = 10.9 => x+y = 250*10.9 = 2725 => 1040+y = 2725 => y = 2725 - 1040 = 1685 => total weight of 150 screws of box 'B', y = 1685 gms Substitute y = 1685 in eqn (2), => average weight of screws of box 'B' = 1685/150 = 11.23 gms (approx) Hence, average weight of screws of box 'B' = 11.23 gms SHORT ANSWER """"""""""""""""" Given data: No. of screws in box 'A', NA = 100 No. of screws in box 'B', NB = 150 Average weight of 100 screws in box 'A', XA = 10.4 gms Average weight of mixed screws, XAB = 10.9 gms Average weight of 150 screws in box 'B', XB = ? Therefore, XAB = (NA XA + NB XB) / (NA + NB) 10.9 = (100*10.4 + 150XB) / (100+150) 10.9 = (1040 + 150XB) / 250 10.9*250 = 1040 + 150XB 2725 = 1040 + 150XB 2725 - 1040 = 150XB 1685 = 150XB XB = 1685/150 = 11.23 gms XB = 11.23 gms - Ratnakar Sharma


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