How many Cl ions are present in 50.0 g FeCl3?

Answer 1

5.568*10^23

Answer 2

To find the number of Cl ions in FeCl3, we first need to calculate the molar mass of FeCl3. Iron (Fe) has a molar mass of approximately 55.85 g/mol, and chlorine (Cl) has a molar mass of approximately 35.45 g/mol. Therefore, the molar mass of FeCl3 is 55.85 + (3 * 35.45) = 126.2 g/mol. Next, we determine how many moles of FeCl3 are present in 50.0 g by dividing the mass by the molar mass: 50.0 g / 126.2 g/mol ≈ 0.396 mol. Since there are 3 Cl ions in every FeCl3 molecule, there are approximately 0.396 mol * 3 = 1.19 mol of Cl ions. Finally, we use Avogadro's number (6.022 x 10^23 molecules/mol) to find the number of Cl ions: 1.19 mol * 6.022 x 10^23 Cl molecules/mol = approximately 7.16 x 10^23 Cl ions.