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0.285 mol.
The solution to this problem can be found through what is called dimensional analysis.
The first thing that needs to be identified is the atomic weight (or molar mass) of SiO2. This can be found in any chemistry text book (particularly the Periodic Table) or even a quick online search (I like to use wikipedia). While it is possible to find the specific atomic weight of the molecule SiO2, I find it simpler just to look up the atomic weights of the individual atoms in the molecule. Starting with silicon (Si), the atomic weight is 28.0855 g/mol. Oxygen (O) has the atomic weight of 15.9994 g/mol. Now, all one needs to do is add up the atomic weights of all the individual atoms to find the total atomic weight of the molecule. For SiO2, this would be 28.0855 g/mol + 15.9994 g/mol + 15.9994 g/mol (since there are 2 oxygen atoms). Notice also that I included the units. In dimensional analysis, it is very important to keep track of units.
This gives you a total of 60.0843 g/mol. Now we have identified the molar mass of the molecule SiO2. The units of the molar mass is g/mol, and we want to find how many moles (mol) are found in a certain mass (g) of SiO2. Now the dimensional analysis really comes into play.
Start with the values that are given in the question: 17.1 g SiO2. We can now convert this number to mols using the molar mass we identified previously: 60.0843 g/mol SiO2. Put into equation form:
17.1g SiO2 | 1 mol SiO2 _ or (17.1 g SiO2 x 1 mol SiO2)/60.0843 g SiO2
¯¯¯¯¯¯¯¯¯|60.0843 g SiO2
With this arrangement, we can see that the units of "g SiO2" will cancel out, and you will be left with "mol SiO2", which is exactly what you are trying to find! And the answer is: 0.285 mol.
Wiki User
∙ 14y ago
Wiki User
∙ 9y agoThe Atomic Mass of silicon dioxide, SiO2 is 28.1 + 2(16.0) = 60.1Amount of SiO2 = mass of pure sample/molar mass = 11/60.1 = 0.183mol
There are 0.183 moles of SiO2 in a 11 gram pure sample.
Wiki User
∙ 14y agoDo you mean the type of Mole that digs up your garden? If this is yes then you have an infestation.
Wiki User
∙ 14y ago.159 mol times 60.1 grams= 9.5559 grams
Wiki User
∙ 9y agoThe answer is 0,203 moles.
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