One mole is 6.02 × 1023 of anything. One mole of atoms is 6.02 × 1023 atoms, one mole of rice is 6.02 × 1023 grains, one mole of shoes is 6.02 × 1023 shoes.
So you take 12 and multiply it with 6.02 × 1023 to get 7.22 × 1024
To convert the mass of a carbon dioxide to moles takes two steps. First, sum the molecular weights of carbon and oxygen (oxygen's atomic weight is added twice because there are two oxygen atoms in the molecule). Then, simply divide the mass by the number calculated. The result is the number of moles of CO2
To convert moles of a substance into grams you first need to figure out its molecular mass. Then you can use this equation: grams(g)=moles(n) X molecular mass For example, 1 mole of Carbon (which has a molecular mass of 12) has a mass of 12 grams.
185 grains = about 11.987 grams.
There are approximately 5,443.11 grams in 1 12 pounds.
A medium strawberry typically weighs around 12 grams.
To find the total mass of 12 moles of CO2, you would multiply the molar mass of CO2 (44 g/mol) by the number of moles (12 moles). This gives: 44 g/mol x 12 mol = 528 grams. Therefore, the total mass of 12 moles of CO2 would be 528 grams.
To find the number of moles in 6.5 grams of CO2, you first need to calculate the molar mass of CO2, which is 44.01 g/mol. Then, divide the given mass by the molar mass to get the number of moles. In this case, 6.5 grams / 44.01 g/mol = 0.148 moles of CO2.
Atomic mass of C = 14g/mol Atomic mass of O = 16g/mol Molecular mass of CO2 = 12 + 2(16) = 44g/mol mass = number of moles x molecular mass mass = 3 mol x 44g/mol = 132g
Apply the equation moles -= mass(g) / Mr Algebraically rearrange mass(g) = Moles X Mr We have 2 moles Mr(CO2) = 44 ( 12 + (2 x 16) = 44) Hence substituting mass(g) = 2moles X 44 mass = 88 grams.
The formula for methane shows that each molecule of it contains 5 atom: 1 carbon atom and 4 hydrogen atoms. The gram molecular mass of methane is 16.04. Therefore, 28 grams of methane contains 28/16.04 moles of methane and 5 times this number, or 8.7, "moles of atoms", to the justified number of significant digits.
to work out the number of moles, you divide the mass by the relative atomic mass so 200 divided by 44 = 4.55 moles
13.3g C + O2 = CO2 m(C)=4g => n(C)=4/12=0,333mol m(O2)=10.67g => n(O2)=10.67/28=0,381mol we have excess of oxigen n(CO2)=n(C)=0,333 m(CO2)=0.333*40=13.3g
For every 1 mole of CH4 that reacts, 1 mole of CO2 is produced. Therefore, 4 moles of CH4 will produce 4 moles of CO2. To calculate the mass of CO2 produced, you would need to multiply the moles of CO2 by its molar mass (44 g/mole) to get the total mass produced.
In order to figure this out, you must do dimensional analysis. Here it is: 3.0 moles He x 4.0026 grams/ mole He = 12 grams
Balanced equation. C + O2 -> CO2 22.2 grams carbon (1 mole C/12.01 grams)(1 mole CO2/1 mole C) = 1.85 moles carbon dioxide produced -------------------------------------------------
First, find out how many moles of C2H6 that you have: Carbon is 12 grams per mole, and H is 1 gram per mole, so C2H6 is (2*12 + 6*1)grams = 30 grams per mole. So you have (77.28/30 = 2.58) moles. Every 2 moles of C2H6 reacts wilth 7 moles of O2 so it will react with 7/2*2.58 moles = 9.02 moles of O2.O2 is 32 grams per mole, so (9.02 moles)*(32 grams/mole) = 288.64 grams.
The balanced equation is: 2C + O2 -> 2CO2. First, determine the moles of C and O2: 4g C / 12 g/mol = 0.33 mol C and 10.67g O2 / 32 g/mol = 0.33 mol O2. From the balanced equation, 2 moles of C produces 2 moles of CO2, so 0.33 mol C will produce 0.33 mol CO2. Since CO2 has a molar mass of 44 g/mol, the total grams of CO2 produced will be: 0.33 mol CO2 x 44 g/mol = 14.52 grams of CO2.