M means mol/litre, you have 250ml. so divide .125 by 1000, x250 to get the moles. then multiply by molecular weight of copper sulphate
2.1g
Molarity = moles of solute(CuSO4)/volume of solution(Liters) 0.967 grams CuSO4 (1 mole CuSO4/159.62 grams) = 0.00606 moles CuSO4 Molarity = 0.00606 moles/0.020 liters = 0.303 Molarity
M = moles solute/ Liters solution 1 mL= 0.001 L 0.990M x 0.001 L =9.9 x 10^-4 moles CuSO4 9.9 x 10^-4 *2 = 0.00198 solute particles *When you dissolve 1 mole CuSO4 in water, it dissolves into 1 mol of Cu+ ions and 1mol of SO4- ions, which gives you twice as many moles of solute particles- which is why you multiply 9.9 x 10^-4 by 2. Hope this helps
Yes. They do not contain the same proportion of CuSO4, however. The moles of CuSO4 . 5 H2O are more massive.
For starters, you know that 0.05000-mol L − 1 solution of copper(II) sulfate contains 0.05000 moles of copper(II) sulfate, the solute, for every 1 L = 10 3 mL of the solution.
HCl + CuSO4
CuSO4 . 2H2O
CuSO4
CuSO4 is ionic.
CuSO4 is copper (II) sulfate. The balanced equation for CuSO4 with water is CuSO4 + H2O reacts to become Cu+2 + HSO4-2 + OH-.
CuSO4 is water soluble. CaCO3 is not.
CuSO4 is a salt of weak base(copper hydroxide) and strong acid(sulphuric acid)....the Ph of the solution of cuso4 will be acidic....
CuSO4 is the chemical formula of copper(II) sulfate.