How many helium balloons does it take to lift 5 pounds?

Answer 1

At 25 degrees Celsius (77 Fahrenheit) and standard pressure (101.3 kPa) one pound of helium would fill 2768 Liters (731) Gallons It depends on how big you want to fill the balloons, the pressure of the balloons the temperature and a range of other things.

Answer 2

At standard conditions:

22.4 Liters of air weighs approximately 29 grams

22.4 Liters of helium weighs 4 grams

29 grams - 4 grams = 25 grams

That means that each 22.4 Liters of helium provides a buoyant force of 25 grams. 22.4 Liters / 25 grams = 0.896 Liters/gram

There are 454 grams in 1 pound

454 grams/pound x 0.896 Liters/gram = 407 Liters/pound

If you hook 407 1-Liter helium balloons to the 1-pound object, it would neither sink nor float. To lift the weight, you'd need "more than 407 1-Liter balloons".

This presumes that the weight of the balloons is figured into the 1 pound. If not, you'll need to find the weight of the 407+ empty balloons.

Since you get the same result with one balloon with a capacity of 407 liters + 1 liter, I say again that the number of balloons is irrelevent unless you state their capacity as part of the question.

Answer 3

The mass the balloons can lift depends on the mass of the air displaced by the balloons.

Mass lift-able + mass of balloons = total mass of air displaced.

Mass of balloons = Total Volume X Density of helium

Mass of air displaced = Total volume X Density of air.

Density of helium = 1.79 X 10^(-4) Kg/m^3 No: 0.1786 kg/m3 (0 °C, 101 kPa)

Density of air = 1.2 Kg/m^3 No: dry air has a density of 1.28 kg/m3 (0 °C, 101 kPa)

1 pound = 0.45 Kg

Volume = Mass lift-able/ (air density - helium density)

= 0.45/(1.2 - 1.79X10-4) = 0.38m^3. No: 0.454/(1.28 - 0.179) = 0.412 m3

You will need enough helium balloons to cover a total volume of about at least 0.4m^3. This assumes that the temperature of the helium and the air is room temperature. I don't know what sized balloons you are considering, but we can say that:

No. of Balloons = total volume/volume per balloon.

If you use roughly spherical balloons of radius 10cm, then the volume per balloon is about 0.004m^3, and the number of balloons needed is about 100. But as i said, without knowing the size of the balloons you intended, i cant really say how much you would need.

Answer 4

A normal helium balloon can lift approximately 14 grams. As a result, lifting 5 pounds (about 2268 grams), would require over 162 balloons. Note, however, that this is an estimate and may vary between different balloon types made by different manufacturers, as well as by how fully the balloon is inflated.

Answer 5

The weight of the balloons must equal the weight of the cup of water.

WH2O = ( 8.338 lbf/gal ) ( 1 gal / 16 cups )( 1.0 cup H2O ) = 0.5211 lbf

dAIR = ( 14.7 psia ) ( 28.97 lbm/lbmol )/ ( 10.73 psia- ft^3 / lbmol - R ) ( 529.7 R )

dAIR = 0.0749 lbm / ft^3 @ 14.7 psia and 70.0 F

wAIR = ( dAIR ) ( g / gc ) = 0.0749 lbf/ ft^3

WAIR = ( NB )( VB* ) ( wAIR )

Let VB* = 0.2 ft^3 per balloon

WAIR = WH2O = (NB ) ( VB* ) ( wAIR )

NB = ( 0.5211 lbf ) / ( 0.2 ft^3 /balloon ) ( 0.0749 lbf/ft^3 )

NB = 34.8 ~ 35 balloons <---------------

Answer 6

It would take approximately 82 helium balloons to lift 5 pounds. This assumes that each helium balloon can lift approximately 0.06 pounds.

Answer 7

it took 53 12" helium balloons to lift a pound, you have to add the weight of the string and balloons

Answer 8

this is a guess i think it would take about 7 with helium in

Answer 9

you need to give dimensions (volume), find the lift given by one cubic inch of helium and find out from there.

Answer 10

125781 balloons