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Any number of joules, no matter how small, will raise the temperature
of the water. The total number required in order to accomplish the job
depends on the final temperature you want to see. The higher that is,
the more energy it will take to reach it.
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∙ 10y ago
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How much thermal energy is required to boil 2.83 kg of water from 50c?
2830 g of water raised through 50 degrees C would use 2830 x 50 calories. But then to boil the water away to steam completely requires another 550 calories per gram, which is 2830 x 550 calories. To convert to Joules, use 4.2 Joules per calorie.
What is Water absorption coefficient formula?
If the water is not already at boiling temperature, then you will need equations 1 and 2. If the water is already at boiling temperature, you will only need equation 2.1. Q = m X C X ΔTThis equation is used to calculate how much energy is required to change the temperature of a given object, of given mass, by a given number of degrees.Q = the total amount of energy required, in joulesm = mass, in grams, of the object being heated (in this case, the water)C = the specific heat of the object (for water, 4.186)ΔT = the total change in temperature2. Q = 2.257 joules X mThe 2.257 in this equation is the heat of vaporization of water: that is, the amount of energy, required per gram of water, to boil water: 2.257 joules per gram. If you were using this equation for a different substance, you would have to look up its heat of vaporization, and substitute it in this equation.Q = the amount of energy required, in joulesm = mass, in grams, of the waterFor example, suppose you were asked to calculate how much energy it would take to boil 256 grams of water which is currently at 40 degrees Celsius. We know that the boiling temperature of water is 100 degrees Celsius; therefore the change in temperature, ΔT, is 100 - 40, which equals 60. Calculate as follows:Q = 256 grams X 4.186 X 60°CQ = 64296.96 joulesThis is how much energy it will take to raise the temperature of the water from 40°C to 100°C. Now calculate how much energy it will take to boil the water once it reaches 100°C:Q = 2.257 joules X 256 gramsQ = 577.792 joulesWe now take the energy required to raise the temperature of the water from 40°C to 100°C and add it to the energy required to boil the water:64296.96 joules + 577.792 joules = 64874.752 joulesConvert to kilojoules:64875.752 joules / 1000 = 64.875752 kilojoulesRound to 64.88 kilojoules.If you are required to express your answer in scientific notation, then express it as6.488 x 103 kilojoules.
Does it take more energy to heat the water to 100 degrees Celsius or to boil it?
q (heat energy in Joules) = mass * specific heat * change in temp 1st problem: q = (100 g H2O)(4.180 J/gC)(100 C - 50 C) = 20900 Joules ---------------------- 2nd problem: q = (100 g H2O)(4.180 J/gC)(70 C - 60 C) = 4180 Joules --------------------- As you can see from 50 C to 100 C takes much more heat energy as one would intuitively think, 20900 J/4180 J = 5 times as much energy.
Can you boil the water at room temperature?
yes,at room temperature by decreasing the pressure we can boil the water.
Does water boil at a lower level above sea level?
First understand that the boiling of water occurs when the energy of water molecules is equal to the vapour pressure... (i.e energy of water is equal to the external pressure due to the atmosphere)... above sea level the atmospheric pressure is lower hence low energy is required... hence water boil at low temperature...
How many joules are required to boil 21.1 g of water at 100 C?
The needed heat is 47,65 Joules.
How much thermal energy is required to boil 2.83 kg of water from 50c?
2830 g of water raised through 50 degrees C would use 2830 x 50 calories. But then to boil the water away to steam completely requires another 550 calories per gram, which is 2830 x 550 calories. To convert to Joules, use 4.2 Joules per calorie.
Does it it take more energy to heat the water to 100 degrees celsius or boil it?
If by "boil" you mean have it all evaporate, that takes MUCH more energy. For example, to increase the temperature of one gram of water from 20 to 100 degrees Celsius, you need 4.2 joules/gram/degree times 80 degrees = about 336 joules; then, to evaporate all the water, you need an additional 2257 joules.
An electric jug full of water needs 480000 joules to bring it to boil The element power is 1 Kilowatt how long will the jug take to boil?
1 kilowatt = 1000 joules per second, so it will take 480 seconds. (8 minutes).
How many kilojoules to boil 1 liter water?
That's going to depend on what temperature the water starts from.
The temperature required to boil water at?
100 degrees Celsius
Can you boil a pint of water on a 60watts peltier unit?
With enough insulation you can in theory boil any amount of water with any amount of energy, given enough time.The key is to supply more energy to the water than it looses.It takes 2260 joules to boil 1 cc of water, joules can be described at watt-seconds.One pint of water is approximately 473 cc, so that will requite 1,068,980 Joules to boil.Given perfect insulation; it would take 17816 seconds / 297 minutes / 5 hours to boil the water with a 60 watt heating element.Assuming that you do not use perfect insulation and given the fact that a peltier element won't give out all 60 watts on the one side, i'd have to say;No you can't boil a pint of water on a 60 watt peltier unit.
What is Water absorption coefficient formula?
If the water is not already at boiling temperature, then you will need equations 1 and 2. If the water is already at boiling temperature, you will only need equation 2.1. Q = m X C X ΔTThis equation is used to calculate how much energy is required to change the temperature of a given object, of given mass, by a given number of degrees.Q = the total amount of energy required, in joulesm = mass, in grams, of the object being heated (in this case, the water)C = the specific heat of the object (for water, 4.186)ΔT = the total change in temperature2. Q = 2.257 joules X mThe 2.257 in this equation is the heat of vaporization of water: that is, the amount of energy, required per gram of water, to boil water: 2.257 joules per gram. If you were using this equation for a different substance, you would have to look up its heat of vaporization, and substitute it in this equation.Q = the amount of energy required, in joulesm = mass, in grams, of the waterFor example, suppose you were asked to calculate how much energy it would take to boil 256 grams of water which is currently at 40 degrees Celsius. We know that the boiling temperature of water is 100 degrees Celsius; therefore the change in temperature, ΔT, is 100 - 40, which equals 60. Calculate as follows:Q = 256 grams X 4.186 X 60°CQ = 64296.96 joulesThis is how much energy it will take to raise the temperature of the water from 40°C to 100°C. Now calculate how much energy it will take to boil the water once it reaches 100°C:Q = 2.257 joules X 256 gramsQ = 577.792 joulesWe now take the energy required to raise the temperature of the water from 40°C to 100°C and add it to the energy required to boil the water:64296.96 joules + 577.792 joules = 64874.752 joulesConvert to kilojoules:64875.752 joules / 1000 = 64.875752 kilojoulesRound to 64.88 kilojoules.If you are required to express your answer in scientific notation, then express it as6.488 x 103 kilojoules.
Why does water boil faster in the mountains than the city?
There is Less atmospheric pressure on a mountain. As pressure goes down, so does the temperature required to boil water.
Does the water boil faster with more water?
Slower, the more water, the more time required to reach boiling temp.
How many natural gas therms are required to boil water?
0.00863 kg/s
How many minutes are required to boil water at a rolling boil to kill most?
5 min is usually recommended, but more might be better.
