To calculate the energy released when the steam cools to water, you need to consider the specific heat capacity of water and steam. The equation Q = mcΔT can be used, where Q is the energy released, m is the mass, c is the specific heat capacity, and ΔT is the change in temperature. Once you have the energy released, you can convert it to joules.
The specific heat capacity of water is 4.18 J/g°C. First, calculate the heat energy required to cool the water from 80.0°C to 60.0°C using the formula: q = mcΔT, where q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the temperature change. Then, convert the heat energy from joules to kilojoules.
An air conditioner does not have a specific temperature setting; rather, it cools the air to a desired temperature set by the user. Therefore, an air conditioner set to 60 degrees will produce colder air than one set to 70 degrees because it will cool the air to a lower temperature.
To calculate the heat released, you can use the formula Q = mcΔT, where Q is the heat, m is the mass, c is the specific heat capacity (0.128 J/g°C for lead), and ΔT is the temperature change. First, convert the mass to kilograms (85.0 g = 0.085 kg) and then calculate Q using the specific heat capacity of lead to get the answer in joules. Finally, convert joules to kilojoules (1 kJ = 1000 J) to find the heat released.
The density of water increases as it cools from 4 degrees Celsius to 0 degrees Celsius. At 4 degrees Celsius, the density of water is 999.972 kg/m³, and at 0 degrees Celsius the density is 999.8395 kg/m³.
As the solid particle cools from -250 degrees Celsius to -273.15 degrees Celsius, the particles will lose kinetic energy and slow down, causing them to vibrate less and move closer together. At -273.15 degrees Celsius, the particles will reach absolute zero and stop all motion, resulting in a state of minimum energy and temperature known as absolute zero.
energy = mass x specific heat x temperature change = 45 x 4.181 x 11 J = 2069.595 J
The specific heat capacity of water is 4.18 J/g°C. First, calculate the heat energy required to cool the water from 80.0°C to 60.0°C using the formula: q = mcΔT, where q is the heat energy, m is the mass, c is the specific heat capacity, and ΔT is the temperature change. Then, convert the heat energy from joules to kilojoules.
No, water's density decreases as it cools. Water reaches its maximum density at around 4 degrees Celsius, and as it cools further, the water molecules form a crystalline structure, causing the density to decrease.
Generally speaking, yes. Magma that cools quickly will produce small, "fine grained" crystals.Magma which cools slowly will generally produce rocks with larger, visible to the naked eye, crystals.This is because while magma is cooling, crystals are forming. Generally, crystal which have more time to grow will be larger. Therefore, generally, the slower magma cools, the bigger the crystals will be. The faster lava cools, the less time crystals have to grow and are thus smaller, "fine grained".
25 degrees Celsius is typically considered comfortable or mild, but not cool. Cool temperatures are usually considered to be around 15-20 degrees Celsius.
I like 85 degrees. It cools you and yet you don't get the shivers.
To calculate the heat lost, you need to use the formula: Q = mcΔT where: Q = heat lost m = mass of granite (3580 kg) c = specific heat capacity of granite (approx. 790 J/kg°C) ΔT = change in temperature (41.2 - (-12.9) = 54.1°C) Plug in the values and calculate to find the heat lost in joules.
super-cooled
These are called sweat glands.
Minerals are formed from magma when the lava cools and hardens to produce a solid
These are called sweat glands.
To calculate the energy released when iron cools, we use the formula ( Q = mc\Delta T ), where ( m ) is the mass, ( c ) is the specific heat capacity of iron (approximately 450 J/kg·°C), and ( \Delta T ) is the change in temperature. Here, ( m = 3.50 , \text{kg} ), ( \Delta T = 110 - 22 = 88 , \text{°C} ). Thus, ( Q = 3.50 \times 450 \times 88 = 138600 , \text{J} ). Therefore, approximately 138,600 joules are given off.