The atomic weight of silver is 107,8682 g/mol
To convert grams to moles:
moles Ag=35,5 g Ag1 mol= 0,329 mol Ag107,8682 g
moles Ag=47 g Ag/107,8682
= 0,436 mol Ag
0.000467 mole = 4.67x10^-4 moles
4.67x10^-4 moles x 6.02x10^23 atoms/mole = 2.81x10^20 atoms
The total number of atoms in 0.000467 mol Ag is 2,8.1020.
47,97 g of molybdenum equal to 2 moles.
4.37 g Ag
Multiply the moles Ag by its molar mass, 107.87 g/mol.
0.0405 mol Ag x (107.87 g Ag)/(1 mol Ag) = 4.37 g Ag (rounded to three significant figures)
There are 2.812*10^20 atoms.
31.49g
Silver is a metal element. There are 47 electrons in a single atom.
Typically, yes. The best conductors are precious metals like Au, Ag, and Cu.
isotope of silver
Control rods are neutron absorbing materials used the check the operation of a nuclear reactror. Some examples: Ag-Cd-In (especially for CANDU reactors), boron carbide and other boron compounds, lanthanides compounds, hafnium compounds, etc.
Ag 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p6 5s1 4d10or simply,[Kr] 5s1 4d10The atomic number of silver is 47, which it means it has 47 protons. A neutral silver atom will also have 47 electrons. Its electron configuration is [Kr]4d105s1.
How many moles is in 0.0688 Ag Cl
The equivalent of 68,3 g Ag is 0,633 moles.
The answer is 6,31 moles Ag.
6,2 moles of silver
The amount of moles is also defined as n = m/M, wheren - amount of moles,m - the mass of the substance,M - the atomic mass of the substance (Ag - 107.8682 g/mol), thereforem = n×M = 0.263×107.8682 = 28,369 grams of Ag.
According to the periodic table, silver (Ag) has an atomic mass of about 108 grams per mole. If you have 802 grams, set up a direct proportion where 108/1=802/x and solve for x. You get about 7.43 moles of silver.
Oxidation-reduction reaction:Ag^+(aq) + Al(s) ===> Ag(s) + Al^3+ or looked at another way... 3AgNO3(aq) + Al(s) ===> Al(NO3)3(aq) + 3Ag(s) moles AgNO3 present = 92.8 g x 1 mole/170 g =0.546 moles moles Al present = 1.34 g x 1 mole/26.9 g = 0.0498 moles Al is limiting based on mole ratio of 3 AgNO3 : 1 Al moles Ag(s) produced = 0.0498 moles Al x 3 moles Ag/mole Al = 0.1494 moles Ag mass of Ag = 0.1494 moles Ag x 108 g/mole = 16.1 g Ag formed
The mass of 2,65 Ag moles is 285,85 g.
If you meant 8.9 * 10^24, then there are 14.78 moles. 8.9 e24 (# of atoms) / 6.02 e23 (# of atoms in a mole) = 14.78 (# of moles)
280g Ag
I assume you mean 3.55 grams of silver. Don't forget your units! Silver (Ag, #47) has an atomic mass of about 108 grams per mole. Set up a direct proportion: 108/1=3.55/x, where x is the unknown number of moles in 3.55 grams Ag. Solve for x to get approx. 0.033 moles Ag. Multiply this number by Avogadro's constant of 6.02x1023 to get the number of representative particles. So, 0.033(6.02x1023)=1.99x1022 atoms of silver.
First from atoms to mole (Avogadro's number)2.3*10+24 (atoms) / 6.022*10+23 (atoms/mole) = 3.82 mole Agand from mole to gram (via molar mass)3.82 mole * 107.9 g/mole = 412 g Ag