The atomic weight of silver is 107,8682 g/mol
To convert grams to moles:
moles Ag=35,5 g Ag1 mol= 0,329 mol Ag107,8682 g
isotope of silver
No, silver (Ag) and gold (Au) are not good insulators. They are both metals that are known to be good conductors of electricity due to the presence of free electrons that can move easily through the material. Insulators, on the other hand, are materials that do not allow the flow of electricity easily.
There are a total of 3 silver atoms in Ag3. Since each silver atom has 47 electrons, the total number of electrons in Ag3 would be 3 * 47 = 141 electrons.
A particle with 47 protons and a +1 charge is a silver ion, specifically silver-47 or Ag+1.
No, conductivity is an intensive property because it does not depend on the amount of the substance present. It is a characteristic that is independent of the size or mass of the sample being measured.
To convert moles to grams, you need to use the molar mass of silver (Ag), which is 107.87 g/mol. Multiply the number of moles by the molar mass to find the grams. Therefore, 0.263 moles of Ag is equivalent to 0.263 moles * 107.87 g/mol ≈ 28.4 grams of silver.
The balanced equation for the reaction is: Cu + 2AgNO3 -> Cu(NO3)2 + 2Ag Calculate the molar mass of Cu and Ag (Cu = 63.55 g/mol, Ag = 107.87 g/mol). Using the molar ratio of Cu to Ag (1:2), convert the mass of Cu to moles, then use the molar ratio to find the moles of Ag produced. Finally, convert moles of Ag to grams using the molar mass of Ag to find the grams of silver produced.
The equivalent of 68,3 g Ag is 0,633 moles.
Given 2Ag2O(s) --> 4Ag(s) + O2(g), and 5.50g of reactant, you get 5.5/232gmol-1 (molar mass reactant)=0.0237mol, times(2) (stoichiometric ratio)=0.0474mol Ag, times(108gmol-1) (atomic mass silver)=approx. 5.12g silver.
The answer is 6,31 moles Ag.
To find the number of atoms in 0.0001 grams of silver (Ag), first determine the number of moles in 0.0001 grams using the molar mass of Ag (108 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. So, 0.0001 g of Ag is equal to 6.94 x 10^16 Ag atoms.
6,2 moles of silver
The amount of moles is also defined as n = m/M, wheren - amount of moles,m - the mass of the substance,M - the atomic mass of the substance (Ag - 107.8682 g/mol), thereforem = n×M = 0.263×107.8682 = 28,369 grams of Ag.
To find the number of moles, we first need to calculate the number of moles of Ag atoms using Avogadro's number (6.022 x 10^23 atoms/mol). Number of moles = 4.4910e23 atoms Ag / (6.022 x 10^23 atoms/mol) ≈ 0.746 moles of Ag.
Oxidation-reduction reaction:Ag^+(aq) + Al(s) ===> Ag(s) + Al^3+ or looked at another way... 3AgNO3(aq) + Al(s) ===> Al(NO3)3(aq) + 3Ag(s) moles AgNO3 present = 92.8 g x 1 mole/170 g =0.546 moles moles Al present = 1.34 g x 1 mole/26.9 g = 0.0498 moles Al is limiting based on mole ratio of 3 AgNO3 : 1 Al moles Ag(s) produced = 0.0498 moles Al x 3 moles Ag/mole Al = 0.1494 moles Ag mass of Ag = 0.1494 moles Ag x 108 g/mole = 16.1 g Ag formed
The mass of 2,65 Ag moles is 285,85 g.
Quite a few moles of silver if you mean, 4.59 X 10^25 atoms of silver. 4.59 X 10^25 atoms silver (1 mole Ag/6.022 X 10^23) = 76.2 moles of silver ----------------------------