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The atomic weight of silver is 107,8682 g/mol

To convert grams to moles:

moles Ag=35,5 g Ag1 mol= 0,329 mol Ag107,8682 g

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How many grams of silver are in 0.263 mole of Ag?

To convert moles to grams, you need to use the molar mass of silver (Ag), which is 107.87 g/mol. Multiply the number of moles by the molar mass to find the grams. Therefore, 0.263 moles of Ag is equivalent to 0.263 moles * 107.87 g/mol ≈ 28.4 grams of silver.


Copper will react with silver nitrate to form copper nitrate and silver From this reaction 127.1 grams of copper will produce how many grams of silver?

The balanced equation for the reaction is: Cu + 2AgNO3 -> Cu(NO3)2 + 2Ag Calculate the molar mass of Cu and Ag (Cu = 63.55 g/mol, Ag = 107.87 g/mol). Using the molar ratio of Cu to Ag (1:2), convert the mass of Cu to moles, then use the molar ratio to find the moles of Ag produced. Finally, convert moles of Ag to grams using the molar mass of Ag to find the grams of silver produced.


How many moles of silver (Ag) are equivalent to 68.3 g Ag?

The equivalent of 68,3 g Ag is 0,633 moles.


How many grams of Ag can be formed from 5.50 grams of Ag2O in the equation 2Ag2O s 4Ag s O2 g?

Given 2Ag2O(s) --> 4Ag(s) + O2(g), and 5.50g of reactant, you get 5.5/232gmol-1 (molar mass reactant)=0.0237mol, times(2) (stoichiometric ratio)=0.0474mol Ag, times(108gmol-1) (atomic mass silver)=approx. 5.12g silver.


How many moles of silver (Ag) are present in a sample of 3.8 10 to the power of twenty four atoms Ag?

The answer is 6,31 moles Ag.


How many ag atoms are there in 0.0001 grams of Ag.Molar mass of Ag is 108 gram per mole?

To find the number of atoms in 0.0001 grams of silver (Ag), first determine the number of moles in 0.0001 grams using the molar mass of Ag (108 g/mol). Then, use Avogadro's number (6.022 x 10^23 atoms/mol) to convert moles to atoms. So, 0.0001 g of Ag is equal to 6.94 x 10^16 Ag atoms.


How many moles of Ag are produced when starting with 6.2 moles of AgNO3?

6,2 moles of silver


What is the mass in grams of silver found in 0.263 mol of Ag?

The amount of moles is also defined as n = m/M, wheren - amount of moles,m - the mass of the substance,M - the atomic mass of the substance (Ag - 107.8682 g/mol), thereforem = n×M = 0.263×107.8682 = 28,369 grams of Ag.


How many moles of Ag contain 4.4910e23 atoms Ag?

To find the number of moles, we first need to calculate the number of moles of Ag atoms using Avogadro's number (6.022 x 10^23 atoms/mol). Number of moles = 4.4910e23 atoms Ag / (6.022 x 10^23 atoms/mol) ≈ 0.746 moles of Ag.


How many grams of silver can be produced from the reaction of 92.8 g of silver nitrate with 1.34 g of aluminum?

Oxidation-reduction reaction:Ag^+(aq) + Al(s) ===> Ag(s) + Al^3+ or looked at another way... 3AgNO3(aq) + Al(s) ===> Al(NO3)3(aq) + 3Ag(s) moles AgNO3 present = 92.8 g x 1 mole/170 g =0.546 moles moles Al present = 1.34 g x 1 mole/26.9 g = 0.0498 moles Al is limiting based on mole ratio of 3 AgNO3 : 1 Al moles Ag(s) produced = 0.0498 moles Al x 3 moles Ag/mole Al = 0.1494 moles Ag mass of Ag = 0.1494 moles Ag x 108 g/mole = 16.1 g Ag formed


What is the mass of 2.65 moles of Ag(s)?

The mass of 2,65 Ag moles is 285,85 g.


How many moles of Ag contains 4.591025 atom of Ag?

Quite a few moles of silver if you mean, 4.59 X 10^25 atoms of silver. 4.59 X 10^25 atoms silver (1 mole Ag/6.022 X 10^23) = 76.2 moles of silver ----------------------------