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How many moles are in 47.0 grams of Ag?

Updated: 8/10/2023
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11y ago

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The atomic weight of silver is 107,8682 g/mol

To convert grams to moles:

moles Ag=35,5 g Ag1 mol= 0,329 mol Ag107,8682 g

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11y ago
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11y ago

moles Ag=47 g Ag/107,8682

= 0,436 mol Ag

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7y ago

0.000467 mole = 4.67x10^-4 moles
4.67x10^-4 moles x 6.02x10^23 atoms/mole = 2.81x10^20 atoms

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7y ago

The total number of atoms in 0.000467 mol Ag is 2,8.1020.

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7y ago

47,97 g of molybdenum equal to 2 moles.

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6y ago

4.37 g Ag

Multiply the moles Ag by its molar mass, 107.87 g/mol.

0.0405 mol Ag x (107.87 g Ag)/(1 mol Ag) = 4.37 g Ag (rounded to three significant figures)

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7y ago

There are 2.812*10^20 atoms.

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11y ago

31.49g

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1y ago
the answer is 72g

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Q: How many moles are in 47.0 grams of Ag?
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How many grams of silver can be produced from the reaction of 92.8 g of silver nitrate with 1.34 g of aluminum?

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How many moles of Ag in 8.9 x 1024 atoms Ag?

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What is the mass of 2.6 moles of Ag?

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I assume you mean 3.55 grams of silver. Don't forget your units! Silver (Ag, #47) has an atomic mass of about 108 grams per mole. Set up a direct proportion: 108/1=3.55/x, where x is the unknown number of moles in 3.55 grams Ag. Solve for x to get approx. 0.033 moles Ag. Multiply this number by Avogadro's constant of 6.02x1023 to get the number of representative particles. So, 0.033(6.02x1023)=1.99x1022 atoms of silver.


How many grams are therein 2.31024 atoms of silver?

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