The amount of heat energy produced from electrical energy depends on the efficiency of the system. If we assume 100% efficiency, then all 3000 joules of electrical energy would be converted into heat energy. Thus, 3000 joules of electrical energy would produce 3000 joules of heat energy.
Each fission of a U235 nucleus produces 200 Mev which in terms of Joules is 3.2 x 10-11 Joules. This is a very small amount, which shows just how many fissions are occurring every second, for a reactor which produces 3000 Mw thermal
The kinetic energy of the roller coaster can be calculated using the formula KE = 0.5 * mass * velocity^2. Plugging in the values, KE = 0.5 * 3000 kg * (30 m/s)^2 = 1,350,000 Joules.
To find the number of photons being radiated per second, you need to calculate the energy of each photon first. Since the light bulb emits 100 watts (100 joules per second), and each photon has an energy of about 4.86 x 10^-19 joules for visible light, you can divide the total energy emitted per second by the energy of each photon to find the number of photons emitted.
The largest capacitor available on the market is the Maxwell Technologies BCAP3000 P300 K04. It has a capacitance of 3000 farads, a voltage rating of 2.7 volts, and a maximum energy storage of 2700 joules.
If this is about the mass-equivalent of energy, you need to do the following: convert the 10 kg to the equivalent energy in joules, using the formula e = m times c squared; then divide the energy you get by 1000 joules, to find how many seconds it will take you. To convert that to hours, divide the result by 3600 (since there are 3600 seconds in an hour). The "physics" answer above is not the biological answer because (wild guess) a pound of fat comes from 3000 calories. There is a lot of extra matter needed to support the energy in a person.
Each fission of a U235 nucleus produces 200 Mev which in terms of Joules is 3.2 x 10-11 Joules. This is a very small amount, which shows just how many fissions are occurring every second, for a reactor which produces 3000 Mw thermal
The voltage is not relevant, only the power (wattage). At 3 kW = 3000 watts, this means 3000 joules per second (J/s), as 1 watt = 1 J/s.CommentThe voltage is relevant! A 3kW electric fire, rated at 230 V, will only produce 3 kW at that rated voltage.
To calculate the total energy consumed in joules, we first convert the power from kilowatts to watts: 3 kW = 3000 watts. Then we multiply the power by the time to get the total energy: 3000 W * 2 hours = 6000 Wh. Finally, we convert watt-hours to joules by multiplying by 3600 (1 Wh = 3600 J): 6000 Wh * 3600 = 21,600,000 joules.
The kinetic energy of the roller coaster can be calculated using the formula KE = 0.5 * mass * velocity^2. Plugging in the values, KE = 0.5 * 3000 kg * (30 m/s)^2 = 1,350,000 Joules.
I will use this formula. Some conversion will be required. ( I only know specific heat iron in J/gC ) q(Joules) = mass * specific heat * change in temperature Celsius 3 kilograms cast iron = 3000 grams q = (3000 g)(0.46 J/gC)(120 C - 30 C) = 124200 Joules (1 kilojoule/1000 joules) = 124.2 kilojoules of energy needed ===========================
The kinetic energy of the diver can be calculated using the formula: KE = 0.5 * mass * velocity^2. Plugging in the values for the mass (60 kg) and velocity (10 m/s), we get KE = 0.5 * 60 * 10^2 = 3000 J. Thus, the kinetic energy of the 60-kg diver falling at 10 m/s is 3000 Joules.
To find the number of photons being radiated per second, you need to calculate the energy of each photon first. Since the light bulb emits 100 watts (100 joules per second), and each photon has an energy of about 4.86 x 10^-19 joules for visible light, you can divide the total energy emitted per second by the energy of each photon to find the number of photons emitted.
3000 joules(J)
3000 joules(J)
The Dell Dimension 3000 made its debut in 2004.
The largest capacitor available on the market is the Maxwell Technologies BCAP3000 P300 K04. It has a capacitance of 3000 farads, a voltage rating of 2.7 volts, and a maximum energy storage of 2700 joules.
Trick question--The answer is none. Indeed, energy in the form of heat is produced by the car stopping. But no energy is required to stop it. The brake pads, and drums or discs absorb energy and get hot.