Work is equal to force x distance. If the force is specified in Newtons, and the distance in meters, then the work is in Joules.
Work is equal to force x distance. If the force is specified in Newtons, and the distance in meters, then the work is in Joules.
Work is equal to force x distance. If the force is specified in Newtons, and the distance in meters, then the work is in Joules.
Work is equal to force x distance. If the force is specified in Newtons, and the distance in meters, then the work is in Joules.
The work done is calculated using the formula: work = force x distance. In this case, the force is 100N and the distance is 5m. Therefore, the work done is 100N x 5m = 500 Joules.
Work performed = Force x displacement = 100 x 5 = 500 J (joule)
Yes, friction can be involved, as one of the forces. For example, if I push against this heavy desk in front of mine with a force of 100N, and it doesn't budge, that means there is a contrary force of 100N. That force, of course, is friction.
To calculate the work done, we need to consider the force applied by the girl minus the force of friction. The net force is 300N - 200N = 100N. Work done = force x distance. Therefore, the work done is 100N x 750m = 75,000 joules.
F = 100N The cm must be converted to meters because pressure is measured in Pascals (Pa), which are N/m2. Pa = F/m2 = N/m2 40cm = 0.4m 50cm = 0.5m Area (A) = .40m x .50m = 0.20m2 Pressure = F/A = 100N/0.20m2 = 500N/m2 = 500Pa
The work done is calculated using the formula: work = force x distance. In this case, the force is 100N and the distance is 5m. Therefore, the work done is 100N x 5m = 500 Joules.
Work performed = Force x displacement = 100 x 5 = 500 J (joule)
Yes, friction can be involved, as one of the forces. For example, if I push against this heavy desk in front of mine with a force of 100N, and it doesn't budge, that means there is a contrary force of 100N. That force, of course, is friction.
If the box is sliding along at a constant speed, the net force acting on the box is zero.If the net force was not zero, the box would either be speeding up or slowing down.Non-zero net forces acting on objects cause the objects to accelerate. Therefore, if the net forces is not zero, the velocity of the object could not be constant.
To calculate the work done, we need to consider the force applied by the girl minus the force of friction. The net force is 300N - 200N = 100N. Work done = force x distance. Therefore, the work done is 100N x 750m = 75,000 joules.
Gravity, normal, and friction forces
F=m*a a=F/m = 300N/3000kg=0.1m/s^2
F = 100N The cm must be converted to meters because pressure is measured in Pascals (Pa), which are N/m2. Pa = F/m2 = N/m2 40cm = 0.4m 50cm = 0.5m Area (A) = .40m x .50m = 0.20m2 Pressure = F/A = 100N/0.20m2 = 500N/m2 = 500Pa
If: 100n = 300 Then divide both sides of the equation by 100 to find the value of n:- n = 3
100N roughly on earth
The output force is 100 N.
n = 6050 = 100 Using the criss cross multiplication trick we get 50X60=3000 and 100 X n=100n 3000 = 100n 100 = 100 So 3000÷100=30 and 100n÷100=n. n=30 or 60% of 50 is 30