Work is equal to force x distance. If the force is specified in Newtons, and the distance in meters, then the work is in Joules.
Work is equal to force x distance. If the force is specified in Newtons, and the distance in meters, then the work is in Joules.
Work is equal to force x distance. If the force is specified in Newtons, and the distance in meters, then the work is in Joules.
Work is equal to force x distance. If the force is specified in Newtons, and the distance in meters, then the work is in Joules.
If a force of 40 N acts through a distance of 10 m, then 400 joules of work result.
It makes no difference what's on the other side of the force, what its mass is, how
much it weighs, or the purpose of the whole exercise.
Work = (force) x (distance)
Both the force and distance are given in the question.
Work = (30 N) x (10 m) = 300 newton-meters = 300 joules.
The mass of the crate doesn't matter.
Work = (force) x (distance)
If the force is 20N and it acts through 10m, then the work is
(20 x 10) = 200 newton-meters or 200 joules.
The mass (or weight) of the crate is irrelevant.
I suggest you use conservation of energy. Calculate the mechanical work you do (the energy you apply), as force x distance. Subtract the friction force, also force x distance (but in this case, the relevant force is the force of friction). Any remaining energy is kinetic energy.
How much work is performed when a sixty kg crate is pushed ten m with a force of thirty N?
Work = Force * distance
Work = 30N * 10 m 300 N-m
Work is equal to force x distance. If the force is specified in Newtons, and the distance in meters, then the work is in Joules.
ZERO...
NIL
No frickin idea
Yes, friction can be involved, as one of the forces. For example, if I push against this heavy desk in front of mine with a force of 100N, and it doesn't budge, that means there is a contrary force of 100N. That force, of course, is friction.
Work performed = Force x displacement = 100 x 5 = 500 J (joule)
F = 100N The cm must be converted to meters because pressure is measured in Pascals (Pa), which are N/m2. Pa = F/m2 = N/m2 40cm = 0.4m 50cm = 0.5m Area (A) = .40m x .50m = 0.20m2 Pressure = F/A = 100N/0.20m2 = 500N/m2 = 500Pa
100N is 22.481 pounds.
The acceleration is 0. That also means that the net force is 0N since the gravity Force is 100N down and the bag of nails is 100N, the air resistance must be 100N up to balance it out and create the net force of 0N
Yes, friction can be involved, as one of the forces. For example, if I push against this heavy desk in front of mine with a force of 100N, and it doesn't budge, that means there is a contrary force of 100N. That force, of course, is friction.
Work performed = Force x displacement = 100 x 5 = 500 J (joule)
If the box is sliding along at a constant speed, the net force acting on the box is zero.If the net force was not zero, the box would either be speeding up or slowing down.Non-zero net forces acting on objects cause the objects to accelerate. Therefore, if the net forces is not zero, the velocity of the object could not be constant.
F = 100N The cm must be converted to meters because pressure is measured in Pascals (Pa), which are N/m2. Pa = F/m2 = N/m2 40cm = 0.4m 50cm = 0.5m Area (A) = .40m x .50m = 0.20m2 Pressure = F/A = 100N/0.20m2 = 500N/m2 = 500Pa
Gravity, normal, and friction forces
F=m*a a=F/m = 300N/3000kg=0.1m/s^2
If: 100n = 300 Then divide both sides of the equation by 100 to find the value of n:- n = 3
100N is 22.481 pounds.
100N roughly on earth
The acceleration is 0. That also means that the net force is 0N since the gravity Force is 100N down and the bag of nails is 100N, the air resistance must be 100N up to balance it out and create the net force of 0N
n = 6050 = 100 Using the criss cross multiplication trick we get 50X60=3000 and 100 X n=100n 3000 = 100n 100 = 100 So 3000÷100=30 and 100n÷100=n. n=30 or 60% of 50 is 30
16.6666666666666N or 1/6