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Work is equal to force x distance. If the force is specified in Newtons, and the distance in meters, then the work is in Joules.

Work is equal to force x distance. If the force is specified in Newtons, and the distance in meters, then the work is in Joules.

Work is equal to force x distance. If the force is specified in Newtons, and the distance in meters, then the work is in Joules.

Work is equal to force x distance. If the force is specified in Newtons, and the distance in meters, then the work is in Joules.

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15y ago

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Related Questions

Calculate the amount of work done if you use a 100N force to push a 50kg box 5m across the kitchen floor?

The work done is calculated using the formula: work = force x distance. In this case, the force is 100N and the distance is 5m. Therefore, the work done is 100N x 5m = 500 Joules.


How much work is done when a 100N force pushes a crate 5m across a factory floor?

Work performed = Force x displacement = 100 x 5 = 500 J (joule)


Does friction occur when there are balanced forces?

Yes, friction can be involved, as one of the forces. For example, if I push against this heavy desk in front of mine with a force of 100N, and it doesn't budge, that means there is a contrary force of 100N. That force, of course, is friction.


If a box is sliding along at a constant speed and the force of friction on the box is 100n what is the net force on the box?

If the box is sliding along at a constant speed, the net force acting on the box is zero.If the net force was not zero, the box would either be speeding up or slowing down.Non-zero net forces acting on objects cause the objects to accelerate. Therefore, if the net forces is not zero, the velocity of the object could not be constant.


How much work is done by a little girl using 300 N force pushing her little brother 750 M against 200 N of friction?

To calculate the work done, we need to consider the force applied by the girl minus the force of friction. The net force is 300N - 200N = 100N. Work done = force x distance. Therefore, the work done is 100N x 750m = 75,000 joules.


How can you solve the resistant forces in this unbalanced forces question Timmy is pushing a box at a force of 100N The box is travelling at a speed of 10 meters per second What are the other forces?

Gravity, normal, and friction forces


When a force of 300 N is applied to an object that experiences 200 N of friction what will the net force that will cause the acceleration be?

F=m*a a=F/m = 300N/3000kg=0.1m/s^2


What is the pressure exerted on the floor by a 100N box whose bottom area is 40 cm by 50 cm?

F = 100N The cm must be converted to meters because pressure is measured in Pascals (Pa), which are N/m2. Pa = F/m2 = N/m2 40cm = 0.4m 50cm = 0.5m Area (A) = .40m x .50m = 0.20m2 Pressure = F/A = 100N/0.20m2 = 500N/m2 = 500Pa


How do you show algebraic steps for an equation eg 100n equals 300?

If: 100n = 300 Then divide both sides of the equation by 100 to find the value of n:- n = 3


A 10 kg weighs newtons?

100N roughly on earth


What is the out put force on 100n?

The output force is 100 N.


60 percent of 50 equals n?

n = 6050 = 100 Using the criss cross multiplication trick we get 50X60=3000 and 100 X n=100n 3000 = 100n 100 = 100 So 3000÷100=30 and 100n÷100=n. n=30 or 60% of 50 is 30