Work = force x distance = 20 x 2 = 40 newton-meters = 40 joules
The distance of effort is the distance along the incline plane that you apply force to lift the car. The distance of resistance is the vertical distance that the car is being lifted. In this scenario, the distance of effort is the 4 meters along the incline plane, and the distance of resistance is the vertical height the car is lifted.
The work done is equal to the force needed to lift the mass multiplied by the vertical distance lifted. In this case, the work done is equal to the gravitational force acting on the mass (m x g) multiplied by the vertical distance lifted (1 m). So, the work done would be 1 kg * 9.8 m/s^2 * 1 m = 9.8 Joules.
The work done by the weight lifter can be calculated using the formula: work = force × distance. In this case, the force is the weight being lifted, which is 200 newtons for each weight. The distance lifted is the height, denoted as 'l' meters. Therefore, the total work done by the weight lifter lifting both weights to a height of 'l' meters is 400 newtons multiplied by 'l' meters, resulting in 400l joules of work.
The idea is to divide the output force (the amount of weight it can lift in this case) by the input force.
If the work done to give a box 400J of energy is against gravity, it would be equal to the force required multiplied by the vertical height lifted. This means the work done would depend on the weight of the box and the distance it is lifted.
Force x distance = 100 x 2 = 200 newton-meters = 200 joules.
You need to know the capacity of the pulleys. The pulleys need a total power of over 1000 newtons, if they do then you should be fine.
The distance of effort is the distance along the incline plane that you apply force to lift the car. The distance of resistance is the vertical distance that the car is being lifted. In this scenario, the distance of effort is the 4 meters along the incline plane, and the distance of resistance is the vertical height the car is lifted.
The work done is equal to the force needed to lift the mass multiplied by the vertical distance lifted. In this case, the work done is equal to the gravitational force acting on the mass (m x g) multiplied by the vertical distance lifted (1 m). So, the work done would be 1 kg * 9.8 m/s^2 * 1 m = 9.8 Joules.
The work done by the weight lifter can be calculated using the formula: work = force × distance. In this case, the force is the weight being lifted, which is 200 newtons for each weight. The distance lifted is the height, denoted as 'l' meters. Therefore, the total work done by the weight lifter lifting both weights to a height of 'l' meters is 400 newtons multiplied by 'l' meters, resulting in 400l joules of work.
1400j
force x distance = work 30 N x 0.5 metres = 15joules
The idea is to divide the output force (the amount of weight it can lift in this case) by the input force.
If the work done to give a box 400J of energy is against gravity, it would be equal to the force required multiplied by the vertical height lifted. This means the work done would depend on the weight of the box and the distance it is lifted.
say g=10,mass =10 kg , force up =1000n force down = mg = 10*10=100n force up = 1000n, net force = 900 n up force of 900 n acting on 10kg, using a=f/m , a=900/10, a = 90 m/s^2 you have to include a time in the data, lets say 10s then s=(a*t^2)/2 , s=(90*100)/2 , s = 4 500 meters
chickjenww
No, changing the distance of a ramp in an inclined plane does not affect the amount of work being done. Work done on an object on an inclined plane is only dependent on the vertical height through which the object is lifted, not the distance along the inclined plane. Work done is calculated as the force applied multiplied by the vertical height.