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g at the tallest mountain is 99.7% the value of g at sea level.

The acceleration due to gravity is inversely proportional to r2, where r is the distance between the two objects' centres. The mean radius of the Earth is 6,378 Km. The tallest mountain (Mount Everest) is nearly 9 Km which makes the Earth's radius at the tallest mountain 6,387.

g at sea level (go) is -9.80 m/s2. so g at the tallest mountain (g1) is:

g1 = go x ( 6,3782 / 6,3872 )

g1 = go x 0.9972

g1 = -9.77

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No, there are slight variations, due to (a) the fact that some points are closer to Earth's center (a.1, you may be on a mountain, and a.2, the poles are closer to the Earth's center), (b) the centrifugal pseudoforce, which gets stronger as you approach the equator, and (c) any gravitational anomaly caused by an uneven distribution of masses.


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Related Questions

Does the value of 'g' remain same everywhere on earth?

G i.e force per unit mass on the earth surface......YES.because all calculation is approximately 10


Does the value of a g and G vary.how?

The value of universal gravitational Constant(G) doesn't change it is constant at any place in the universe, it's value is 6.67259 x 10-11Nm2/Kg2 But the value of g varies from from place to place on earth,planet to planet and star to star because g=GM/R2 As G is constant g depends on M=mass of planet,R=radius of planet,so g varies with the change in M and R.


At what altitude above the earth surface the value of 'g' reduces to half of its value at the surface?

The gravitational acceleration, g, decreases with altitude according to the inverse square law. At an altitude equal to the radius of the Earth (about 6371 km), the value of g would reduce to half of its surface value. This is because the gravitational attraction between the Earth and an object weakens as the distance between them increases.


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No, there are slight variations, due to (a) the fact that some points are closer to Earth's center (a.1, you may be on a mountain, and a.2, the poles are closer to the Earth's center), (b) the centrifugal pseudoforce, which gets stronger as you approach the equator, and (c) any gravitational anomaly caused by an uneven distribution of masses.


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