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Through displacement of another volume.

For example, say you wish to measure the volume of an unknown object. Given a flask capable of measuring volume with reasonable precision, you could fill that flask with water up to a certain volume. Adding the unknown object and submerging it completely would "displace" the water, i.e. cause the water level in the flask to rise. According to the Archimedes Principle, the new volume on the flask subtracted by the old volume renders the total volume of the unknown.

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14y ago
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15y ago

there is the water displacement method, i think you are confusing volume with mass/density. anyway, place the object in a beaker, and see how much water it displaces, that will tell you.

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Q: How the volume of a heavy irregularly shaped object may be determined experimentally are there any limitations?
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How the volume of an irregullar solid can be determined?

By water displacement. Pour a certain volume of water into a graduated cylinder, and record that volume. Now, place the irregularly shaped object into the cylinder, and record the level to which the water now rises. Take the difference between those two volumes, and you now have the volume of your irregularly shaped object.


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If the object in question is water proof, and small enough. You can measure the amount of displaced water when it is placed in a tank full of water, this may not work for a lot of things but it can help when attempting to measure some objects.


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Using a graduated beaker, add water sufficent to totally immerse the object. Note the initial volume of the water without the object. Put the irregularly-shaped object in the beaker and note the final volume. The difference between the final and initial readings is the volume of the object. This is only possible if the object is not soluble in water. If it is, use some other fluid in which it is not soluble.


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