The work done is equal
Areas
yes have a smaller area:)
F1/A1=F2/A2 F2=F1(A2/A1) plug in the numbers and you have your ans. NOTE: do you know how to find the Area when given diameter? that is kinda imp. for this problem.
Mechanical pressure from the primary piston
You get the force exerted by a hydraulic piston by taking the pressure times the surface area of the piston.
Areas
yes have a smaller area:)
F1/A1=F2/A2 F2=F1(A2/A1) plug in the numbers and you have your ans. NOTE: do you know how to find the Area when given diameter? that is kinda imp. for this problem.
796.2 N/m^2
33,250.
You reduce the diameter of the small piston. Or reduce the diameter and increase the travel of the small piston if you want the large piston to maintain it's previous range of travel.
A hydraulic piston is also known as a servo or a motor.
There are many parts to hydraulic cylinders. The main parts are the barrel, the base, the head, the piston, the piston rod, and numerous seals. They operate using hydraulic fluid.
http://www.engineeringtoolbox.com/hydraulic-force-calculator-d_1369.html
Pressure Exertion: When a force is applied to a small piston or area on one side of the hydraulic device, it creates pressure within the enclosed fluid. The pressure is given by the formula P = F/A, where F is the force applied and A is the area over which the force is applied. Transmission of Pressure: The pressure generated is transmitted through the incompressible hydraulic fluid to all parts of the system. The pressure is the same throughout the fluid due to Pascal's law. Larger Area on the Output Side: The hydraulic fluid transmits this pressure to a larger piston or area on the other side of the hydraulic device. Since pressure is force per unit area, the larger area results in a higher force output. The output force (F_out) can be calculated using the same pressure formula (P = F_out/A_out), rearranged to solve for F_out: F_out = P * A_out.
Mechanical pressure from the primary piston
Mechanical pressure from the primary piston