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The work done is equal

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Q: How will the work done on the input piston compare to the work done by the output piston in a hydraulic device?
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Related questions

Is the ratio of output force to input force of a hydraulic press equal to the ratio of the output and input piston areas?

Areas


What will happen to the size of the force of the exerted by a hydraulic system if the output piston has a smaller area?

yes have a smaller area:)


A hydraulic device has an input piston with an area of 20 cm2 and an output piston with an area of 100 cm2 An input force of 1000 N will provide an output force of 5000 N.How will the pressure on?

F1/A1=F2/A2 F2=F1(A2/A1) plug in the numbers and you have your ans. NOTE: do you know how to find the Area when given diameter? that is kinda imp. for this problem.


In a hydraulic device the surface area of the small piston is 20cm and the surface area of the piston is 80cm to lift a 400 N barrel placed on the large piston you must apply a force of?

796.2 N/m^2


Calculate the force output by the larger piston of a hydraulic lift when a force of 700 n is exerted on the smaller piston the areas of the two pistons are 20 cm squared and 950 cm squared?

33,250.


How can you increase the force a hydraulic device produces without increasing the size of the force you apply to the small piston?

You reduce the diameter of the small piston. Or reduce the diameter and increase the travel of the small piston if you want the large piston to maintain it's previous range of travel.


What is hydraulic ram servo?

A hydraulic piston is also known as a servo or a motor.


What are the parts of hydraulic cylinders?

There are many parts to hydraulic cylinders. The main parts are the barrel, the base, the head, the piston, the piston rod, and numerous seals. They operate using hydraulic fluid.


Hydraulic cylinder retract force on piston with rod size reduced by half at piston end?

http://www.engineeringtoolbox.com/hydraulic-force-calculator-d_1369.html


How pneumatic and hydraulics systems multiply force?

Pressure Exertion: When a force is applied to a small piston or area on one side of the hydraulic device, it creates pressure within the enclosed fluid. The pressure is given by the formula P = F/A, where F is the force applied and A is the area over which the force is applied. Transmission of Pressure: The pressure generated is transmitted through the incompressible hydraulic fluid to all parts of the system. The pressure is the same throughout the fluid due to Pascal's law. Larger Area on the Output Side: The hydraulic fluid transmits this pressure to a larger piston or area on the other side of the hydraulic device. Since pressure is force per unit area, the larger area results in a higher force output. The output force (F_out) can be calculated using the same pressure formula (P = F_out/A_out), rearranged to solve for F_out: F_out = P * A_out.


If hydraulic pressure is lost in the primary circuit how does the secondary piston actuate?

Mechanical pressure from the primary piston


How is the secondary piston actuated if hydraulic pressure is lost in the primary circuit?

Mechanical pressure from the primary piston